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lora16 [44]
3 years ago
15

341÷5 what's the remander​

Mathematics
2 answers:
Maksim231197 [3]3 years ago
6 0

Answer:

its 1

Step-by-step explanation: 341/5= 68 r1

weqwewe [10]3 years ago
4 0

Answer:

68.2

Step-by-step explanation:

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Which fractions are equivalent to 10/12? Select each correct answer. ​ ​2/3​ ​5/6​ ​12/24​ ​30/36​ ​50/60​ ​60/84​
Yuri [45]

Answer:

[See Below]

Step-by-step explanation:

✦ Turn into decimals:

  • \frac{10}{12}=0.83
  • \frac{2}{3} =0.67
  • \frac{5}{6} =0.83
  • \frac{12}{24} =0.5
  • \frac{30}{36} =0.83
  • \frac{50}{60} =0.83
  • \frac{60}{84} =0.71

So \frac{10}{12} ≈ \frac{5}{6},\frac{30}{36},and,\frac{50}{60}.

~<em>Hope this helps Mate. If you need anything feel free to message me. </em>

4 0
3 years ago
Hat term can you add to StartFraction 5 over 6 EndFraction x minus 4 to make it equivalent to One-half x minus 4?
kolezko [41]

Answer:

\dfrac{-x}{3}should be added to the given equation.

Step-by-step explanation:

Let a is added to the given equation.

According to the given condition,

\dfrac{5x}{6}-4+a=\dfrac{x}{2}-4\\\\a=\dfrac{x}{2}-4+4-\dfrac{5x}{6}\\\\a=\dfrac{x}{2}-\dfrac{5x}{6}\\\\a=\dfrac{3x-5x}{6}\\\\a=\dfrac{-2x}{6}\\\\a=\dfrac{-x}{3}

So, \dfrac{-x}{3}should be added to the given equation.

8 0
3 years ago
Which statements about the data sets are true? Check all that apply.
Yuri [45]

Answer: 2, 3, 4, 5

Step-by-step explanation:

I just did it i'm positive it correct :)

Hope this helps.

7 0
3 years ago
What is the area of the following figure?
Snowcat [4.5K]

Answer:

16.56‬

Step-by-step explanation:

The area of the square is 2 × 2

The area of the circle is-

A=πr²

A=3.14 × 2²

A=3.14 × 4

A=12.56

You don't need to divide it by half because there are two half circles so it would be a whole circle

12.56 + 4 = 16.56

Sorry if it is wrong

7 0
3 years ago
Read 2 more answers
What is the surface area of the right cylinder below. radius 3 height 7​
lina2011 [118]

Answer:

160 sq. uits

Step-by-step explanation:

160 sq. uits é a resposta

4 0
3 years ago
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