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RUDIKE [14]
1 year ago
8

Find parametric equations for the sphere centered at the origin and with radius 3. Use the parameters s and t in your answer. x(

s, t) = y(s, t) = , and z(s, t) = , where |
Mathematics
1 answer:
Harlamova29_29 [7]1 year ago
4 0

Answer:

Step-by-step explanation:

In general (x, y, z) = (p ·cos s ·sin t, p· sin s· sin t, p · cos t) where p is radius

x(s, t)= 3 ·cos s ·sin t

y(s, t)= 3· sin s· sin t

z(s, t) = 3· cos t

Where, radius is 3, s ∈ [0,2π), and t ∈ [0, π]

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What’s 325 devied by 13 and how do you solve it helpppp
lesya692 [45]

Answer:

the answer is 25

Step-by-step explanation:

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2 years ago
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Complete the table and graph the function y = 2x + 1 with the domain: 0, 1, 2, 5, 7
Oxana [17]

Answer:

Set it up as a table and insert the numbers one by one

4 0
3 years ago
What is the inverse function of d(x) = 2x - 4?
Naddik [55]
Let d(x) = 2x - 4

Or

y = 2x - 4

We have replace x = y

x = 2y - 4

Now Isolate "y"

x + 4 = 2y

Pass "2" dividing

(x + 4) / 2 = y

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Or

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7 0
3 years ago
Who wants brainlist and points
postnew [5]

Answer:

6 times 10^3

Step-by-step explanation:

You multiply 3 and 2 together and 10^7 and 10^-4 together. 3x2 is equal to 6 and 10^7 times 10^-4 is the same as 10^7-4 which is equal to 10^3. Therefore, the answer is 6 times 10^3.

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3 0
2 years ago
How to find the square root of complex numbers?? Find the square root of (6+8i) ??​
ivann1987 [24]

Answer:

2 \sqrt{2}  + i \sqrt{2}

Step-by-step explanation:

The square of a complex number is a complex number. Here, we have:

{(a + bi)}^{2}  = 6 + 8i

{a}^{2}  + 2abi -  {b}^{2}  = 6  + 8i

We then have this system of equations:

{a}^{2}  -  {b}^{2}  = 6

2ab = 8

Solving this system:

ab = 4

b =  \frac{4}{a}

{a}^{2}  -  {( \frac{4}{a}) }^{2} = 6

{a}^{2}  -  \frac{16}{ {a}^{2} } = 6

{a}^{4}  - 16 =  6{a}^{2}

{a}^{4}  - 6 {a}^{2}  - 16 = 0

( {a}^{2}  - 8)( {a}^{2}  + 2) = 0

{a}^{2}   = 8

a = 2 \sqrt{2}

b =  \frac{4}{2 \sqrt{2} } =  \sqrt{2}

6 0
2 years ago
Read 2 more answers
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