This will be a 4th degree polynomial. Our root of x = 7 in factorization form is (x-7). Our root of x = -11 in factorization form is (x+11) and the last one is a complex number. According to the conjugate root theorem, if we have 2+8i, we also HAVE to have 2-8i. In factorization form that first one is (x-(2+8i)) which simplifies to (x-2-8i). Its conjugate in factorization form is (x-2+8i). Now we will FOIL all that out. Let's start with the (x-2-8i)(x-2+8i). That multiplies out to

. We have to combine like terms here to shorten that a bit.

. i^2 is equal to -1, and -1(64) = -64. Now we have

. That is

. Now let's FOIL in another factorization.

. That comes out to

. One more term to go!

. That, finally, is

.
Answer:
Step-by-step explanation:
idk man ill let u know tho
Answer: C
For the people who want only one answer and not 2 for the question if you can only submit one answer :)
Answer:
Step-by-step explanation:
A_n = a + (n-1)d
a_n = -2n + 3
when n=1
a_1 = a = -2(1) + 3 = -2 + 3 = 1
when n = 2
a-_2 = -2(2) + 3 = -4 +3 = -1
a_2 = a + d
therefore,
a + d = -1
d = -1 - a
d = - 1 - 1
d = -2
Therefore the sequence is ,
1 , -1, -3, -5, -7.......
14 - 6 = 8 and she gives 1/5 to each student so if there is 8 students 3 would be left without clay