Omar throws a softball from a starting height of 8 feet, with an initial velocity of 18 feet per second. Which of the following
equations shows the path of the softball? H(t) = −16t2 + 26 H(t) = −16t2 + 26t H(t) = −16t2 + 8t + 18 H(t) = −16t2 + 18t + 8
2 answers:
The last one! H(0)=8, H'(0)=18 and then the negative term from gravity. Clear? :)
The last one because the y-intercept has to be at 8 so:
H(t) = -16t^2 + 18t + 8
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