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kicyunya [14]
3 years ago
11

Through (-10,2) and perpendicular to the line y-3x=8 in point-slope form

Mathematics
1 answer:
ss7ja [257]3 years ago
5 0
The instructions begin with "Find the equation of the line ... " and should be included in your post.

This new line is perp. to the line y - 3x = 8, or y = 3x + 8.  Slope is 3.
Thus, a line perp to this one would have the slope -1/3.

In point-slope form:  y-2 = (-1/3)(x-[-10]), or    y - 2 = (-1/3)(x+10)   (answer)
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The <em>quadratic</em> equation 3 · x² + 7 · x - 2 = 0 has a <em>positive</em> discriminant. Thus, the expression has two <em>distinct real</em> roots (<em>real</em> and <em>irrational</em> roots).

<h3>How to determine the characteristics of the roots of a quadratic equation by discriminant</h3>

Herein we have a <em>quadratic</em> equation of the form a · x² + b · x + c = 0, whose discriminant is:

d = b² - 4 · a · c     (1)

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If we know that a = 3, b = 7 and c = - 2, then the discriminant is:

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The <em>quadratic</em> equation 3 · x² + 7 · x - 2 = 0 has a <em>positive</em> discriminant. Thus, the expression has two <em>distinct real</em> roots (<em>real</em> and <em>irrational</em> roots).

To learn more on quadratic equations: brainly.com/question/2263981

#SPJ1

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