Find the sum of the interior angles of a quadrilateral with 15 sides?
2 answers:
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Answer:
a = , b = 5, and
= 20
Step-by-step explanation:
f(x) = - x² + b, x ≤ 0 You would use this equation for f(-2). Since -2 is less than 0.
f(x) = - x² + b, x ≤ 0 ← You can ignore the x ≤ 0 part.
f(-2) = - (-2)² + b Input the value -2 as x. The question states that f(-2) =1.
1 = - (-2)² + b So switch f(-2) with 1 on the left side only.
1 = - (4) + b Simplify. Do the exponents first, so (-2)² = 4.
1 = - 4 + b
<u>+4 +4 </u> Do inverse operations
5 = b
Next,
f(x) = 2ax +3, x > 0 You would use his equation for f(2). Since 2 is greater than 0.
f(x) = 2ax +3, x > 0 ← You can ignore the x > 0 part.
f(2) = 2a(2) + 3 Input the value 2 as x.
f(2) = 4a +3 Simplify. The equation states f(2) = 5. So switch f(2) with 5
5 = 4a +3 on the left side only.
<u>-3 - 3</u> Do inverse operations
2 = 4a
=
Divide 4 on both sides to isolate the variable a
= a Simplify
= a
Then,
The second part says to find
Input both the values of a and b
Simplify
20.
The answer for a is , the answer for b is 5, and the answer for
is 20.