3 years ago

I really need help on this question

Mathematics

1 answer:

saul85 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

y = $\frac{1}{4}$ is the equation of a horizontal line, parallel to the x- axis.

A line perpendicular to it will be a vertical line parallel to the y- axis with equation

x = c

where c is the value of the x- coordinates the line passes through.

The line passes through (- 6, - 9) with x- coordinate - 6, thus

x = - 6 ← is the equation of the perpendicular line

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Find the minimum y-value on the graph y=f(x) <br> f(x)= x^2+4x-5

djverab [1.8K]

There are two ways to solve the problem: using calculus and algebra. For this, I'll be using the algebraic way. The function is parabolic, thus the minimum value is the ordinate of the vertex. Using completing the square, we could get the vertex of the parabola.

y = x^2 + 4x - 5y = x^2 + 4x + 4 - 5 - 4y = (x + 2)^2 - 9Vertex is (-2, -9).

Therefore, the minimum value is -9.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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Step-by-step explanation:

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