Sally and her husband Jim left their house at the same time traveling in the same direction. Sally drove at 55mph and Jim drove at 65mph. How many hours was it before Jim was 100 miles ahead of Sally?
1 answer:
Answer:
It will take 10 hours.
Step-by-step explanation:
We know distance = rate * time
Sally's rate = 55
Jim's rate = 65
We want Jim to be 100 miles ahead of Sally
The time will always be the same.
d =Sally's distance
Sally
d = 55t
Jim
d+100 = 65 t
We know have 2 equations with 2 unknowns. Substitute d= 55t into Jim's equations
55t + 100 = 65t
Subtract 55t from both sides.
55t-55t + 100 = 65t-55t
100 = 10t
divide each side by 10
100/10 = 10t/10
10 = t
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Sorry if it is wrong but i hope i was right
