Find the slope of the line connecting (1990,435000) and (2005,482300):
482300-435000 47300
m = ----------------------- = ---------------- = 3153/yr (approx)
2005 - 1990 15 yr
Use the point-slope formula to find the equation of this str. line:
y-435000 = (3153/yr)(x-1990)
The year 2020 is 30 years after 1990. Thus, the expected pop in 2020 is
given by y-435000 = 3153(30) = 94590, so that y = 529590.
Hello this is not question .
Twilight was liked by half the class because if you add up the number of students you get 24 and half of 24 is 12
(Hope this helped)
Answer:
Before we graph 
we know that the slope, mx, could be read as 
. To graph the the equation of the line, we begin at the point (0,0). From that point, because our rise is negative (-1), instead of moving upwards or vertically, we will move downards. Therefore, from point 0, we will vertically move downwards one time. Now, our point is on point -1 on the y-axis. Now, we have 2 as our run. From point -1, we move to the right two times. We land on point (2,-1). Because we need various points to graph this equation, we must continue on. In the end, the graph will look like the first graph given.
For the equation y = 2, the line will be plainly horizontal. Why? Because x has no value in the equation. The variable 
does not exist in this linear equation. Therefore, it will look like the second graph below. We graph this by plotting the point, (0,2), on the y-axis.
