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OverLord2011 [107]
4 years ago
9

Number 4 please :))))))))))))

Mathematics
1 answer:
V125BC [204]4 years ago
7 0
Just write it if i know it i will help you 
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Find the angle of yzv? ​
Eddi Din [679]

Step-by-step explanation:

12a+24a=180

36a = 180

a =5 °

angle of yzv = 24a = 120°

4 0
3 years ago
Angie run 4 miles in 18 minutes how far can she run in 90 minutes
zhuklara [117]
    <u>4</u>  =  <u>x
</u>  18     90

(4 * 90) / 18  = 20  
<u>
</u> x = 20             So Angie can run 20 miles in 90 minutes!<u>

</u>
5 0
4 years ago
-2+y=9 3x-7y=3 solve the system by the substitution
REY [17]

Answer:

80/3 or 26 2/3

Step-by-step explanation:

-2 + y = 9 (subtract y from both sides)

-2 = 9 - y (subtract 9 from both sides)

-2 - 9 = y (multiply both sides by -1)

2 + 9 = y (simplify)

11 = y (substitute)

3x - 7 (11) = 3 (multiply)

3x - 77 = 3 (subtract 3 from both sides)

3x - 80 = 0 (subtract 3x from both sides)

-80 = -3x (multiply both sides by -1)

80 = 3x (divide both sides by 3)

80/3 = x (simplify if needed)

26 2/3 = x

5 0
3 years ago
Tom has a collection of 30 CDs and Nita has a collection of 18 CDs. Tom is adding 1 CD a month to his collection while Nita is a
Marta_Voda [28]
30 + 1x = 18 + 5x
subtract 18 from both sides
30 - 18 + 1x = 18 - 18 + 5x
12 + 1x = 5x
subtract 1x from both sides
12 + 1x - 1x = 5x - 1x
12 = 4x
To clear the multiplication by 4, divide both sides by 4
12/4 = 4x/4
3 = x
It will take 3 months until they have the same amount of CD's
They will each have 33 CD's
8 0
3 years ago
The probabilities that a batch of 4 computers will contain 0, 1, 2, 3, and 4 defective computers are 0.4096, 0.4096, 0.1536, 0.0
Zinaida [17]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i)

And if we replace we got:

E(X) = 0*0.4096 +1*0.4096+ 2*0.1536+ 3*0.0256 +4*0.0016 = 0.8

So we expect about 0.8 defective computes in a batch of 4 selected.

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

Solution to the problem

For this case we have the following distribution given:

X           0             1               2               3             4

P(X)  0.4096    0.4096    0.1536    0.0256    0.0016

And we satisfy that P(X_i) \geq 0 and \sum P(X_i) =1 so we have a probability distribution. And we can find the expected value with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And if we replace we got:

E(X) = 0*0.4096 +1*0.4096+ 2*0.1536+ 3*0.0256 +4*0.0016 = 0.8

So we expect about 0.8 defective computes in a batch of 4 selected.

5 0
4 years ago
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