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OverLord2011 [107]
3 years ago
9

Number 4 please :))))))))))))

Mathematics
1 answer:
V125BC [204]3 years ago
7 0
Just write it if i know it i will help you 
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Calculati lungimea cercului cu raza de 0,(4)cm
natali 33 [55]
<span>0, (4) = 4/9 <span>L circle = 2πR </span><span>L circle = 2 · π · 4/9 </span><span>L circle = 8π / 9 cm
</span></span>L = 2 * pi * R 
<span>L = 2 * pi * 0. (4) cm = 0. (8) pi cm</span>

5 0
3 years ago
Find the area of this circle. Use 3 for a.A = 7r2=11 in[?] in?
liberstina [14]

SOLUTION

We want to find the area of the circle in the picture given.

We have been given the formula as

\begin{gathered} A=\pi r^2 \\ We\text{ are told to take }\pi\text{ as 3} \\  \end{gathered}

From the circle, the radius r = 11 in.

The area of the circle becomes

\begin{gathered} A=\pi r^2 \\ A=\pi\times r^2 \\ A=3\times11^2 \\ A=3\times11\times11 \\ A=363in^2 \end{gathered}

Hence the answer is 363 square-inches

7 0
1 year ago
Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on
insens350 [35]
1) We have that there are in total 6 outcomes If we name the chips by 1a, 1b, 3 ,5 the combinations are: 1a,3 \ 1b, 3 \1a, 5\ 1b, 5\ 3,5\1a,1b. Of those outcomes, only one give Miguel a profit, 1-1. THen he gets 2 dollars and in the other cases he lose 1 dollar. Thus, there is a 1/6 probability that he gets 2$ and a 5/6 probability that he loses 1$.
2) We can calculate the expected value of the game with the following: E=\frac{1}{6}*2- \frac{5}{6} *1. In general, the formula is E= \sum{p*V} where E is the expected value, p the probability of each event and V the value of each event. This gives a result of E=2/6-5/6=3/6=0.5$ Hence, Miguel loses half a dollar ever y time he plays.
3) We can adjust the value v of the winning event and since we want to have a fair game, the expecation at the end must be 0 (he must neither win or lose on average). Thus, we need to solve the equation for v:
0=\frac{1}{6}v -\frac{5}{6} =0. Multiplying by 6 both parts, we get v-5=0 or that v=5$. Hence, we must give 5$ if 1-1 happens, not 2.
4) So, we have that the probability that you get a red or purple or yellow sector is 2/7. We have that the probability for the blue sector is only 1/7 since there are 7 vectors and only one is blue. Similarly, the 2nd row of the table needs to be filled with the product of probability and expectations. Hence, for the red sector we have 2/7*(-1)=-2/7, for the yellow sector we have 2/7*1=2/7, for the purple sector it is 2/7*0=0, for the blue sector 1/7*3=3/7. The average payoff is given by adding all these, hence it is 3/7.
5) We can approach the problem just like above and set up an equation the value of one sector as an unknown. But here, we can be smarter and notice that the average outcome is equal to the average outcome of the blue sector.  Hence, we can get a fair game if we make the value of the blue sector 0. If this is the case, the sum of the other sectors is 0 too (-2/7+0+2/7) and the expected value is also zero.
6) We want to maximize the points that he is getting. If he shoots three points, he will get 3 points with a probability of 0.30. Hence the average payoff is 0.30*3=0.90. If he passes to his teammate, he will shoot for 2 points, with a success rate of 0.48. Hence, the average payoff is 0.48*2=0.96. We see that he should pass to his player since 0.06 more points are scored on average.
7) Let us use the expections formula we mentioned in 1. Substituting the possibilities and the values for all 4 events (each event is the different profit of the business at the end of the year).
E=0.2*(-10000)+0.4*0+0.3*5000+0.1*8000=-2000+0+1500+800=300$
This is the average payoff of the firm per year.
8) The firm goes even when the total profits equal the investment. Suppose we have that the firm has x years in business. Then x*300=1200 must be satisfied, since the investment is 1200$ and the payoff per year is 300$. We get that x=4. Hence, Claire will get her investment back in 4 years.
8 0
3 years ago
Read 2 more answers
Please help me , i just need to past this !
OLga [1]

Answer:

Step-by-step explanation:

i would say c

3 0
3 years ago
Read 2 more answers
What two numbers have 2,3,5 as factors
lukranit [14]
Two numbers with factors 2,3,5 are 30 and 60.
when we multiply 2 x 3 x 5 = 30
we get answer 30 and then again multiply with the number that is greater than 1 is 2 and then we get 2 x 2 x 3 x 5 = 60
So the first two numbers with factors 2, 3 and 5 are 30 and 60.
4 0
3 years ago
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