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Kisachek [45]
3 years ago
9

This pair of figures is similar. Find the missing side.​

Mathematics
2 answers:
Alenkinab [10]3 years ago
7 0

Answer:

x = 2

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

\frac{x}{8} = \frac{4}{16} ( cross- multiply )

16x = 32 ( divide both sides by 16 )

x = 2

Harlamova29_29 [7]3 years ago
6 0

Answer:

x=2

Step-by-step explanation:

so if the bigger one is 16 and the other one is 4 that means you need to multiply 4 by 4 to get 16 so to find x you need to divide the 8 by 4 to find your answer

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The graph of quadratic function p is shown on the grid. (-3, 3) (3, 3) If (x) = x and p(x) = 5(x) + n, what is the value of n?​
aliina [53]

Answer:

Step-by-step explanation:

4 0
3 years ago
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Pairs of integers with a product of 48
LekaFEV [45]
(-2)(-24)
(-3)(-16)
(-4)(-12)
(-6)(-8)
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1*48
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Find the area of a trapezoid with base 1 side = 10 base 2 side = 16 and 3​
mart [117]

Answer:

Area of Trapezoid is 39 unit²

Step-by-step explanation:

Given as :

For A Trapezoid

The measure of base side 1 = b_1 = 10 unit

The measure of base side 2 = b_2 = 16 unit

The height of the Trapezoid = h = 3 unit

Let  The Area of Trapezoid = A square unit

<u>Now, From Formula</u>

Area of Trapezoid = \dfrac{1}{2} × (sum of opposite base) × height

I.e A =  \dfrac{1}{2} × (b_1 + b_2) × h

Or, A =  \dfrac{1}{2} × (10 unit + 16 unit) × 3 unit

Or, A =  \dfrac{1}{2} × (26 unit) × 3 unit

Or, A =  \dfrac{1}{2} × 78 unit²

Or, A = \dfrac{78}{2} unit²

I.e A = 39 unit²

So, The Area of Trapezoid = A = 39 unit²

Hence, The Area of Trapezoid is 39 unit² . Answer

6 0
3 years ago
Solve for m: 2m² + 16 = 2m
Goshia [24]

Answer: m = 16

Step-by-step explanation:

2m² + 16 = 2m

2m² - 2m = 16

m = 16

5 0
3 years ago
What is the greatest common factor of the following monomials: 12g^5h^4 g^5h^2
muminat

Answer:

g^5h^2

Step-by-step explanation:

12g^5h^4, g^5h^2

This is one way of doing it. Break down every number and every variable into a product of the simplest factors. Then see how many of each factor appear in both monomials.

12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h

g^5h^2 = g * g * g * g * g * h * h

So far you see every single prime factor of each monomial.

Now I will mark the ones that are present in both. Those are the common factors.

12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h

g^5h^2 = g * g * g * g * g * h * h

The greatest common factor is the product of all the factors that appear in both monomials.

GCF = g * g * g * g * g * h * h = g^5h^2

6 0
3 years ago
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