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2 years ago

Is the equation cosine theta - sine theta =1 an identity? Explain

1 answer:

7 0

Answer: No, because an identity is an equation that is always true and cos(theta) - sin(theta) does not always equal 1.

Hope this helped! :)

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PLEASE HELP DONT COPY ALL PREVIOUSE ANSWERS ARE WRONG For the past ten years, Michelle has been tracking the average annual rain

OLEGan [10]

Answer:

The answer to this question is that the average rainfall varies by 0.07 each year.

Step-by-step explanation:

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3 years ago

Given A. 88 B. 64 C. 92 D. 52

victus00 [196]

Maybe 88 not sure that is the givin

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2 years ago

Amy reached into a bag, recorded the color of the tile she picked, returned the tile and drew again. These are the tiles she has

Vedmedyk [2.9K]

Answer:

(a) P(next ball with blue) = $\frac{3}{10}$ (b) P(Not to be red) = $1-\frac{2}{5} =\frac{3}{5}$

(c) P(drawing 70 times yellow ball) = $\frac{1}{10} \times 70 = 7$ .

Step-by-step explanation:

Given that,

The total outcomes of the color of tile are :-

Red , Red, Blue, Yellow, Blue, Red, Green, Red, Blue, Green.

From the Question,

Total number of outcomes = 10

(a) What is the probability that her next draw will be blue ?

Red = 4,

Blue = 3,

Green = 2,

Yellow = 1.

P(next ball with blue) = $\frac{3}{10}$ .

(b) What is the probability that her next draw will NOT be red?

P(Red ball) = $\frac{4}{10} = \frac{2}{5}$

But we have to find

P(Not to be red) = $1-\frac{2}{5} =\frac{3}{5}$

(c) If Amy draws 70 more times with the same tiles from the question above, what probability would you expect a yellow?

P(Yellow ball) = $\frac{1}{10}$

drawing it 70 times we get the probability

P(drawing 70 times yellow ball) = $\frac{1}{10} \times 70 = 7$ .

5 0

3 years ago

Matias gets dressed in the dark one morning and chooses his clothes at random. He chooses a shirt(green, red or yellow) a pair o

inn [45]

What is the question here?

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3 years ago

ABCD is a parallelogram. Which statements are true?

jekas [21]

Answer:

Final Answer: Statements 1, 2 and 4 are correct.

Step-by-step explanation:

Finding value of y:

2y + 3 = 15 => 2y = 12 => y = 6;

Finding value of x:

6x + 5 = 77 => 6x = 72 => x = 12;

Statement Number 1:

y² > 2x ? => 6² > 2 * 12 ? => 36 > 24 ?

Yes, 36 is bigger than 24, therefore statement one is correct.

Statement 2:

x = 2y ? => 12 = 2 * 6? => 12 = 12?

Yes, 12 is equal to 12. Statement 2 is correct.

Statement 3:

x + 2 = y + 10 ? => 12 + 2 = 6 + 10? => 14 = 16?

No, 14 is not equal to 16. Statement 3 is incorrect.

Statement 4:

y + 4 > x - 4 ? => 6 + 4 > 12 - 4 ? => 10 > 8 ?

Yes, 10 is bigger than 8. Statement 4 is correct.

If this helped you please rate

Final Answer: Statements 1, 2 and 4 are correct.

5 0

3 years ago