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kotykmax [81]
3 years ago
12

A couple does not wish to spend more than $60 for dinner at a restaurant. if a sales tax of 7% is added to the bill and they pla

n to tip 15% after the tax has been added, what is the most they can spend for the meal? (round your answer to the nearest cent.)
Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0
Hey there!

The first step of this problem would be to add together our two percentages, then convert that percentage into a decimal by dividing by 100. 

15% + 7% = 22%

22 ÷ 100 = 0.22

It can be assumed here that 22% of the cost will be added tax and tip. We can use 0.22 to represent that percentage in our problem. Just multiply that decimal by the maximum amount of money they want to spend, $60, to get the amount that will just be tax and tip. Finally, subtract the tax and tip from $60 to find the most they can spend on the meal itself. 

60 × 0.22 = 13.20

60 – 13.20 = 46.80

The total amount they can spend is 46.80. 

Hope this helped you out! :-)
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Step-by-step explanation:

Distribution would be an increase to find 80% salt.

Where we use 4/5 = 80 but use here 4/5.

We find 19/20 but just say 95 for solution B =

Let x = the number of ounces of Solution A

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x + y = 110        y = 110 - x

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70x + 95 (88 - x) = 8800 make units equal or for start convert decimalization = same units as 2nd multiplied value.

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Conditional distribution: This distribution contrasts from the previous one in the sense that we are restricting the universe of events to specific condition for other variable, making a modification of our marginal results. If we know that throwing a dice will give us a result higher than 2, then to in order to calculate the probability of the dice being a multiple of 3 using that condition, we have two favourable cases (3 and 6) from 4 total possible results (3,4,5 and 6) discarding the impossible values (1 and 2) from this universe since they dont match the condition given (note that the restrictions given can also reduce the total of favourable cases).

The joint distribution calculates the probabilities for two different events (related to two different random variables) occuring simultaneously. If we want to calculate the joint probability of a dice being multiple of 3 and greater than 2 at the same time, our possible cases in this case are 3 and 6 from 6 possible results. We are not discarding 1 or 2 as possible results because we are not assuming, that the dice is greater than 2, that is another condition that we should met in the combination of events.

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