0.00067=67X10^5 so
67X10^5-2.3X10^5
64.7X10^5 which can be expressed as:
6.47X10^6
(not sure if it matters to you or not, but technically we only had two significant figures so it should be rounded to 6.5X10^6)
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
Answer:
can't understand your question click a clear pic of your question
We are given the table that projects the distance of the car per hour. x is associated to time while y is associated to distance. The equation of the line after plotting in MS Excel is y = 900 - 50x. Hence the y-intercept is equal to 900 while the slope is equal to -50. The domain of the function that is x is all positive numbers.
