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GenaCL600 [577]
4 years ago
8

Compare the KE of an 80 kg person walking at 4 m/s with that of the same person moving at 6 m/s.

Physics
1 answer:
Alla [95]4 years ago
7 0
The correct answer is:
<span>KE at 4 m/s less than KE at 6 m/s

In fact, the formula for the kinetic energy is:
</span>K= \frac{1}{2} mv^2
<span>where m is the mass of the person and v his speed.

When the person is moving at 4 m/s, his kinetic energy is:
</span>K= \frac{1}{2} (80 kg)(4 m/s)^2=640 J
instead, when he's moving at 6 m/s, his kinetic energy is:
K= \frac{1}{2}(80 kg)(6 m/s)^2=1440 J

So, the kinetic energy at 4 m/s is less than the kinetic energy at 6 m/s.
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159kg × ( 9.8-4.9)

159kg × 4.9

= 779.1N

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