Compare the KE of an 80 kg person walking at 4 m/s with that of the same person moving at 6 m/s.
1 answer:
The correct answer is:
<span>KE at 4 m/s less than KE at 6 m/s
In fact, the formula for the kinetic energy is:
</span>
<span>where m is the mass of the person and v his speed.
When the person is moving at 4 m/s, his kinetic energy is:
</span>
instead, when he's moving at 6 m/s, his kinetic energy is:
So, the kinetic energy at 4 m/s is less than the kinetic energy at 6 m/s.
<span>KE at 4 m/s less than KE at 6 m/s
In fact, the formula for the kinetic energy is:
</span>
<span>where m is the mass of the person and v his speed.
When the person is moving at 4 m/s, his kinetic energy is:
</span>
instead, when he's moving at 6 m/s, his kinetic energy is:
So, the kinetic energy at 4 m/s is less than the kinetic energy at 6 m/s.
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Answer:
α = 3.27 rad/s²
No
Explanation:
Given that
L= 3 m
Lets take mass of tree = m kg
The torque to mass m = m g .L
The mass moment of inertia of tree ,I
I = mL² kg.m²
We know that
τ = I α
m g .L = mL² .α
α= g/L
Now by putting the value
α = 3.27 rad/s²
No we can find the mass of the from the above information because angular acceleration is not depend on the mass of tree.
