Compare the KE of an 80 kg person walking at 4 m/s with that of the same person moving at 6 m/s.
1 answer:
The correct answer is:
<span>KE at 4 m/s less than KE at 6 m/s
In fact, the formula for the kinetic energy is:
</span>
<span>where m is the mass of the person and v his speed.
When the person is moving at 4 m/s, his kinetic energy is:
</span>
instead, when he's moving at 6 m/s, his kinetic energy is:
So, the kinetic energy at 4 m/s is less than the kinetic energy at 6 m/s.
<span>KE at 4 m/s less than KE at 6 m/s
In fact, the formula for the kinetic energy is:
</span>
<span>where m is the mass of the person and v his speed.
When the person is moving at 4 m/s, his kinetic energy is:
</span>
instead, when he's moving at 6 m/s, his kinetic energy is:
So, the kinetic energy at 4 m/s is less than the kinetic energy at 6 m/s.
You might be interested in
Answer:
(a) The net force is 80.394 N
The acceleration of the crate is 0.804 m/s²
(b) the final velocity of the crate is 5.02 m/s
Explanation:
Given;
mass of the crate, m = 100 kg
applied force, F = 250 N
angle of inclination, θ = 45°
coefficient of friction, μ = 0.12
Applied force in y-direction,
Applied force in x-direction,
The normal force is calculated as;
N + Fy -W = 0
N = W - Fy
N = (100 x 9.8) - 176.78
N = 980 - 176.78 = 803.22 N
The frictional force is given by;
Fk = μN
Fk = 0.12 x 803.22
Fk = 96.386 N
(a) The net force is given by;
Apply Newton's second law of motion;
F = ma
(b) the velocity of the crate after 5.0 s