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Irina18 [472]
4 years ago
12

Why do scientist use models to study atoms

Physics
1 answer:
Vedmedyk [2.9K]4 years ago
6 0
Scientists use models to study atoms, Because atoms are very tiny, and almost impossible to cut open and look inside.. And the center of an atom is the nucleus and that is ever smaller.
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Which of the following best describes reverberation?
Liono4ka [1.6K]

Answer:

There are no appropriate descriptions on the list of choices you've provided.

Explanation:

Reverberation, in psychoacoustics and acoustics, is a persistence of sound after the sound is produced.[1] A reverberation, or reverb, is created when a sound or signal is reflected causing a large number of reflections to build up and then decay as the sound is absorbed by the surfaces of objects in the space – which could include furniture, people, and air.[2] This is most noticeable when the sound source stops but the reflections continue, decreasing in amplitude, until they reach zero amplitude.

4 0
3 years ago
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Inside a spinnet, the hammer is sometimes set to strike multiple strings to increase the instrument's volume. If the 523 Hz note
rodikova [14]

Answer:

4.23 beats / seconds

Explanation:

Frequency heard = f = f₁ - f₂

f₂ = f₁  √ ( F₂ / F₁)

f = f₁ - f₁ √ ( F₂ / F₁) = f₁ ( 1 - √ ( F₂ / F₁) = 523 Hz ( 1 - 0.9919 ) = 4.23 beats / seconds

3 0
3 years ago
If this did not happen, what would be the approximate force on an eardrum of area 0.22 cm2 if a change in altitude of 1500 m tak
jeyben [28]

Complete Question

When you ascend or descend a great deal when driving in a car yours ears "pop," which means that the pressure behind the eardrum is being equalized to that outside. If this did not happen, what would be the approximate force on an eardrum of area .50 cm2 if a change in altitude of 950 m takes place?

Answer:

The value is F    = 0.60 \  N

Explanation:

From the question we are told that

   The area of the ear drum is  A = 0.5 \  cm^2 = 0.50 *10^{-4} \  m^2

    The change in altitude is  \Delta d  = 950 \  m

Generally the change in pressure is mathematically represented as

       \Delta P = \frac{F}{A}

This can also be mathematically represented as

      \Delta P = \rho * g *  \Delta d

So

       \frac{F}{A}     = \rho * g *  \Delta d

=>    F    = \rho * g *  \Delta d  *  A

=>    F    = \rho * g *  \Delta d  *  A

Here \rho is the density of dry air with value  \rho =  1.29 \ kg /m^3

So

     F    = 1.29 * 9.8 *  950  *  0.50 *10^{-4}

=> F    = 0.60 \  N

3 0
3 years ago
How does a rubber rod become negatively charged through friction?
stira [4]
I think it is c I'm only in 7th grade but I'm pretty sure that the answer is c
5 0
4 years ago
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Could I get some help with this
nika2105 [10]

please give me brainlest!!

the answer is A.

4 0
3 years ago
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