Answer:
0.7757 rev/s
Explanation:
d = Diameter of the tornado = 53 m
r = Radius of the tornado = 53/2 = 26.5 m
v = Velocity of wind = 465 km/h
Converting velocity to m/s
Angular velocity
∴ Angular velocity is 0.7757 rev/s
0A: accelerating
AB: constant
BC: decelerating
CD:at rest
DE:accelerating
EF: constant
hope this helps
When the sun, moon, and Earth are lined up (during a new or full moon), the solar tide adds to the lunar tide to produce extremely high tides and very low tides, both of which are known as spring tides.
- Basically describes a situation in astronomy where three celestial bodies align in a straight line as part of a gravitational system. The phrase is frequently used to describe how the Sun, Moon, and Earth are in a straight line.
- The moon is responsible for causing high and low tides. The tidal force is produced by the moon's gravitational pull. Earth and its water protrude outward on both the side that is closest to and farthest from the moon as a result of the tidal force. These watery peaks are high tide
To know more about high tides
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Answer:
Option A applies.
A. Greater than its escape speed from the mass within the volume
Explanation:
Here it is mentioned that the spherical volume is large enough for the space to be considered as homogeneous. Also, the pressure within the volume is negligible, so that will not result into the re collapse of the Universe. Now as per our knowing, Hubble's Law relates the average speed of the particle to the distance R between the Earth and the particle. So, if the particle's speed is greater than it's escape speed from the mass within the volume, then the Universe is bound to re collapse back again. Option A applies.
A jet fighter flies from the airbase A 300 km East to the point M. Then 350 km at 30° West of North.
It means : at 60° North of West. So the distance from the final point to the line AM is :
350 · cos 60° = 350 · 0.866 = 303.1 km
Let`s assume that there is a line N on AM.
AN = 125 km and NM = 175 km.
And finally jet fighter flies 150 km North to arrive at airbase B.
NB = 303.1 + 150 = 453.1 km
Then we can use the Pythagorean theorem.
d ( AB ) = √(453.1² + 125²) = √(205,299.61 + 15,625) = 470 km
Also foe a direction: cos α = 125 / 470 = 0.266
α = cos^(-1) 0.266 = 74.6°
90° - 74.6° = 15.4°
Answer: The distance between the airbase A and B is 470 km.
Direction is : 15.4° East from the North.
