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3 years ago

(Please explain why) A bar magnet is dipolar. This means is has ____ poles.

Physics

2 answers:

Pani-rosa [81]3 years ago

8 0

Answer:

Two poles

Explanation:

The word dipole can be splitted to two; "di" and "pole"; di means 2; hence dipole means 2 poles

A dipolar bar magnet has two poles on the earth surface; these poles are the geomagnetic north pole and the south pole respectively.

In other words, a dipole magnet is a type of magnet in which the opposite poles (which are the North and South poles) are on opposite sides of the magnet.

Away from the surface the dipole becomes distorted. The magnetic field of a bar magnet has a simple configuration known as a dipole field.

earnstyle [38]3 years ago

5 0

Di = two, just like 'bi'. --take di-zygotic twins, or di-atomic + di-sulphide, etc.

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A car initially traveling at 21.4 m/s accelerates at a rate of 4.4 m/s2 for 7.5 seconds. What is the final velocity of the car?

Marysya12 [62]

The car's final velocity is 11.6 m/s in the opposite direction.

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3 years ago

A vertical scale on a spring balance reads from 0 to 250 N. The scale has a length of 15.0 cm from the 0 to 250 N reading. A fis

lesantik [10]

Answer:

Mass of fish=6.252 kg

Explanation:

Force F=0 N to 250 N

Length x=15.0 cm=0.15 m

Frequency f=2.60 Hz

To find

Mass of fish m

Solution

First we need to find spring constant

$k=Force/distance\\k=F/x\\k=250/0.15\\k=1666.7 N/m$

As we know that the time period is given as

$T=2\pi\sqrt{\frac{m}{k} }\\ And\\f_{Frequency} =1/T\\So\\1/f=2\pi\sqrt{\frac{m}{k} }\\1/f^{2}=4\pi^{2}\frac{m}{k}\\ k/f^{2}=4\pi^{2}m\\m=\frac{k}{4\pi^{2}f^{2} } \\m=\frac{1666.7}{4\pi^{2} (2.60)^{2} }\\ m=6.252kg$

4 0

3 years ago

a motor pulls up a block suspended on a string, so that the tension in the string is equal to the qeight force on the block. the

Sindrei [870]

Answer:

Explanation:

Let T be the tension in the string and mg is the weight of the block.

T = mg

By using Newton's second law

T - mg = ma

mg - mg = ma

a = 0

Thus, the acceleration is zero.

8 0

3 years ago

A 1.25 x 10-4 C charge is moving5200 m/s at 37.0° to a magnetic fieldof 8.49 x 10-4 T. What is the magneticforce on the charge?

juin [17]

0.0003321 Newtons

Explanation

We are given the charge, its velocity, and the magnetic field strength and direction. We can thus use the equation to find the force

$\begin{gathered} F=qvBsinθ \\ where\text{ F is the magnetic force} \\ q\text{ is the charge} \\ v\text{ is the velocity of the charge} \\ Bis\text{ the magnetic field} \\ \theta\text{ is the angle} \end{gathered}$

Step 1

Let

$\begin{gathered} q=1.25*10^{-4\text{ }}C \\ v=5200\frac{m}{s} \\ \theta=37\text{ \degree} \\ B=8.49*10^{-4}T \end{gathered}$

now, replace

$\begin{gathered} F=qvBs\imaginaryI n\theta \\ F=1.25*10^{-4}\text{ C*5200 }\frac{m}{s}*8.49*10^{-4}Tsin(37) \\ F=0.0003321\text{ Newtons} \\ \end{gathered}$

so, the answer is

0.0003321 Newtons

I hope this helps you

7 0

1 year ago

I am really struggling with this question because I can't find anything on aphelion and perihelion, it's not a topic we went ove

Hoochie [10]

I have a strange hunch that there's some more material or previous work
that goes along with this question, which you haven't included here.

I can't easily find the dates of Mercury's extremes, but here's some of the
other data you're looking for:

Distance at Aphelion (point in it's orbit that's farthest from the sun):
69,816,900 km
0. 466 697 AU

 Distance at Perihelion (point in it's orbit that's closest to the sun):
46,001,200 km
0.307 499 AU 

Perihelion and aphelion are always directly opposite each other in
the orbit, so the time between them is 1/2 of the orbital period.

Mercury's Orbital period = 87.9691 Earth days

1/2 (50%) of that is 43.9845 Earth days

The average of the aphelion and perihelion distances is

1/2 ( 69,816,900 + 46,001,200 ) = 57,909,050 km
or
1/2 ( 0.466697 + 0.307499) = 0.387 098 AU

This also happens to be 1/2 of the major axis of the elliptical orbit.

3 0

4 years ago