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3 years ago

15 The group of elements called the noble gases

Physics

2 answers:

kogti [31]3 years ago

8 0

Answer:

C. a full outer shell of valence electrons.

Explanation:

The noble gases has a full outer shell so they don't have to react with other elements to gain or loose electrons (to have a full outer shell and be stable).

EastWind [94]3 years ago

6 0

Took the test (C.a full outer shell..

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3 years ago

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Two 2.0kg bodies A and B collide The velocities before the collision are U1=15i+30j and U2=-10j+5.0j After the collision V1=-5.0

Svetllana [295]

Use the law of conservation of momentum. Since the momentum is a linear measure, we can treat each of the dimension separately:

i-direction:

$m_1u_{1i}+m_2u_{2i}=m_1v_{1i}+m_2v_{2i}\\v_{2i} = \frac{m_1u_{1i}+m_2u_{2i}-m_1v_{1i}}{m_2}=\frac{(2\cdot 15-2\cdot10+2\cdot5)kg\frac{m}{s}}{2kg}=10\frac{m}{s}$

j-direction:

$m_1u_{1j}+m_2u_{2j}=m_1v_{1j}+m_2v_{2j}\\v_{2j} = \frac{m_1u_{1j}+m_2u_{2j}-m_1v_{1j}}{m_2}=\frac{(2\cdot 30+2\cdot5-2\cdot20)kg\frac{m}{s}}{2kg}=15\frac{m}{s}$

Answer: Final velocity is: (10i + 15j) m/s

Change in the kinetic energy:

$\Delta E_k = E_{ku}-E_{kv} = \frac{1}{2}m(u_1^2+u_2^2-v_1^2-v_2^2)=\\=\frac{1}{2}2kg(1125+125-425-325)\frac{m^2}{s^2}=500J$

Answer: The system lost 500J worth of kinetic energy in the collision

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3 years ago

The image produced by a convex mirror is always closer to the mirror than it would be in a plane mirror for the same object dist

rosijanka [135]

Answer:

True

Explanation:

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So, this statement is true.

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3 years ago

Select the correct answer.

skelet666 [1.2K]

Answer:

B is the best answer for the question

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3 years ago

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