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kobusy [5.1K]
2 years ago
11

15 The group of elements called the noble gases

Physics
2 answers:
kogti [31]2 years ago
8 0

Answer:

C. a full outer shell of valence electrons.

Explanation:

The noble gases has a full outer shell so they don't have to react with other elements to gain or loose electrons (to have a full outer shell and be stable).

EastWind [94]2 years ago
6 0
Took the test (C.a full outer shell..
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What is the effect on the force of gravity between two objects if the mass of one object remains unchanged while the distance to
Vadim26 [7]

Answer:

The correct answer to the question is

B. It always decreases

Explanation:

To solve the question, we note that the foce of gravity is given by

F_G=\frac{Gm_1m_2}{r^2} where

G= Gravitational constant

m₁ = mass of first object

m₂ = mass of second object

r = the distance between both objects

If the mass of one object remains unchanged while the distance to the second object and the second object’s mass are both doubled, we have

F_{G2} =\frac{Gm_1(2m_2)}{(2r)^2} = \frac{2}{4} \frac{Gm_1m_2}{r^2}

Therefore the gravitational force is halved. That is it will always decrease

4 0
3 years ago
A stationary 6-kg shell explodes into three pieces. One 4.0 kg piece moves horizontally along the negative x-axis. The other two
natta225 [31]

Answer:

-15 m/s

Explanation:

The computation of the velocity of the 4.0 kg fragment is shown below:

For this question, we use the correlation of the momentum along with horizontal x axis

Given that

Weight of stationary shell = 6 kg

Other two fragments each = 1.0 kg

Angle = 60

Speed = 60 m/s

Based on the above information, the velocity = v is

1\times 60 \times cos\ 60 + 1\times 60 \times cos\ 60 - 4\ v = 0

\frac{60}{2} + \frac{60}{2} - 4\ v = 0

v = \frac{60}{4}

= -15 m/s

4 0
3 years ago
Calculate the wavelength of violet light with a frequency of 750×10 to the 12
MaRussiya [10]
Wavelength of any wave = (speed) / (frequency)

Speed of light = 300,000,000 m/sec

Wavelength = 3 x 10 to the 8 / 750 x 10 to the 12 = 4 x 10 to the -7 or 400 nanometers.
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alexandr1967 [171]
The mass of the object will remain the same rather it's on the moon or on the Earth and even in other places. But the weight will change on the moon, so its weight will be different from the one it had on Earth
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3 years ago
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