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liraira [26]
2 years ago
6

How many sides has an equiangular polygon if one of its exterior angles is 25 5/7?

Mathematics
1 answer:
lys-0071 [83]2 years ago
6 0
Step One
Figure out the interior angle
25 5/7 = 25.714285 repeating. The interior angle is the supplement of this angle.

180 - 25.714285 = 154.2857
The formula relating the number of sides and the interior equal angle is

interior equal angle = 180 ( 1 - 2/n) where n is the number of sides. (Google equiangular polygon to find this formula.)

154.2857 / 180 = 1 - 2/n) 
0.8571428 = 6/7 = 1 - 2/n
1/7 = 2/n
n = 14 sides
This figure is regular as well as equiangular.
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Step-by-step explanation:

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3 years ago
I need to know how to solve it and get the answer right to check my work
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3 0
3 years ago
Read 2 more answers
A) how many ways are there to choose 10 players to take the field?
Kruka [31]

A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.

B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

10! 3!

9!1! 1!2! 10! 3!

8!2! 2!1! 10! 3!

7!3! 3!0!

= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =

= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =

= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285 1·2·3

<span>possible choices.</span><span> 
</span>

  


5 0
3 years ago
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