Find the slope of the line through the given points. (-9, -7) and (-11, -13)

Hi. Please I need help with these questions.

ElenaW [278]

Answer:

Q 12 roots of the equation

$2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\$

∝ = $\frac{\sqrt{10} }{2}$

β = $-\frac{\sqrt{10} }{2}$

no matter if u oppose the root

(i) 2( $\frac{\sqrt{10} }{2}$ ) $(-\frac{\sqrt{10} }{2} )^{2}$ +2 $(\frac{\sqrt{10} }{2} )^{2}$ ( $-\frac{\sqrt{10} }{2}$ )+2(

(ii)( $(\frac{\sqrt{10} }{2})^{2}$ - 3 ( $\frac{\sqrt{10} }{2}$ )( $-\frac{\sqrt{10} }{2}$ ) + ( $(-\frac{\sqrt{10} }{2})^{2}$ ) = $\frac{25}{2}$

Q 13 roots of equation

$4x^{2} -3x-4=0\\\alpha = -0.693\\\beta = 1.443$

the roots of the second equation are

x1 = 1/3(-0.693) = -0.231

x2 = 1/3(1.443) = 0.481

the equation is

(x+0.231)(x-0.481)=0

$x^{2}-\frac{1}{4} x-\frac{1}{9}$

4 0

3 years ago

Marisol graphed a scatter plot of the number of hours she rode her

maks197457 [2]

Answer:

lolololololololoolololo

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Use the Fundamental Theorem of Calculus to find the "area under curve" of

lozanna [386]

Answer:

$\displaystyle A = 300$

General Formulas and Concepts:

Calculus

Integrals

Definite Integrals
Area under the curve
Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 6x + 19

Interval [12, 15]

Step 2: Find Area

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^{15}_{12} {(6x + 19)} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{15}_{12} {6x} \, dx + \int\limits^{15}_{12} {19} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 6\int\limits^{15}_{12} {x} \, dx + 19\int\limits^{15}_{12} {} \, dx$
[Integrals] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = 6(\frac{x^2}{2}) \bigg| \limits^{15}_{12} + 19(x) \bigg| \limits^{15}_{12}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle A = 6(\frac{81}{2}) + 19(3)$
Simplify: $\displaystyle A = 300$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

7 0

3 years ago

Ms. Suzuki is buying soda for the pizza party her class earned. She estimates that each of her

olya-2409 [2.1K]

Answer:

6

Step-by-step explanation:

250 mL is 0.25 L or 1/4 L.

1 L is enough for 4 students.

A 2-L bottles is enough for 8 students.

Since 24 students is 3 times 8 students, you need 3 times a 2-liter bottle.

Answer: 3

8 0

2 years ago

Which are the solutions of x2 = –13x – 4? 0, 13 0, –13 StartFraction 13 minus StartRoot 153 EndRoot Over 2 EndFraction comma Sta

klasskru [66]

Solution of the given expression $x^2 = -13x-4$ is $x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}$

Correct options are: Start Fraction negative 13 minus Start Root 153 End Root Over 2 End Fraction comma Start Fraction negative 13 + Start Root 153 End Root

Step-by-step explanation:

We need to find solutions of $x^2 = -13x-4$

We need to solve the quadratic equation and find values of x.

Solving:

$x^2 = -13x-4$

Rearranging the terms:

$x^2+13x+4=0$

Solving the quadratic equation using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a = 1, b= 13 and c=4

putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(13)\pm\sqrt{(13)^2-4(1)(4)}}{2(1)}\\x=\frac{-13\pm\sqrt{169-16}}{2}\\x=\frac{-13\pm\sqrt{153}}{2}\\x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}$

So, Solution of the given expression $x^2 = -13x-4$ is $x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}$

Correct options are: Start Fraction negative 13 minus Start Root 153 End Root Over 2 End Fraction comma Start Fraction negative 13 + Start Root 153 End Root

Keywords: Solving Quadratic Equations

Learn more about Solving Quadratic Equations at:

#learnwithBrainly

5 0

3 years ago

Read 2 more answers