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alekssr [168]
3 years ago
11

0.6(y - 0.2) = 3 - 0.2(y - 1)

Mathematics
2 answers:
otez555 [7]3 years ago
8 0

Answer:

y=4.15

Step-by-step explanation:

0.6(y - 0.2) = 3 - 0.2(y - 1)

0.6y - 0.12 = 3 - 0.2y +0.2

        +0.12 =               +0.12

0.6y =3 - 0.2y +0.32

+0.2y = + 0.2y

0.8y/0.8 = 3.32/0.8

y= 4.15

inna [77]3 years ago
7 0

Answer: y= 4.15

You have to isolate the variable by itself

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Select the correct answer. robin randomly selects a number between 1 and 20. what is the probability that the number selected is
Vlada [557]

The probability that the number selected is the square of a natural number will be  \frac{1}{5}.

<h3 /><h3>What is probability?</h3>

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1.

Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.

P is the probability

F(E) is the favorable event

T(E)is the total event

The probability is found as;

\rm P = \frac{F(E)}{T(E)} \\\\ \rm P = \frac{4}{20)} \\\\ \rm P = \frac{1}{5}

Hence the probability that the number selected is the square of a natural number will be  \frac{1}{5}.

To learn more about the probability link is given below.

brainly.com/question/795909

8 0
2 years ago
Solve for k, m = 3kx/7 - 9
kap26 [50]

Answer:

(7m + 63)/3x = k

Step-by-step explanation:

<em>m=3kx/7 - 9</em>

<u><em>add 9 to both sides:</em></u>

m+ 9 = 3kx/7

<u><em>multiply both sides by 7:</em></u>

7(m+9) = 3kx

<u><em>distribute the 7:</em></u>

7m+63 = 3kx

<u><em>divide both sides by 3x:</em></u>

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3 0
3 years ago
Criterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test. Data: Use the inf
Papessa [141]

The table is missing in the question. The table is provided here :

Group 1        Group 2

 34.86            64.14      mean

 21.99            20.46      standard deviation

  7                    7                n

Solution :

a). The IV or independent variable = Group 1

    The DV or the dependent variable = Group 2

b).

  $H_0: \mu_1 = \mu_2$

  $H_a:\mu_1 < \mu_2$

  Therefore,   $t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{S_2^2}{n_2}}}$

$t = \frac{34.86 - 64.14}{\sqrt{\frac{21.99^2}{7}+\frac{20.46^2}{7}}}$

t = -2.579143

Now,   $df = min(n_1 - 1, n_2 - 1)$

           df = 7 - 1

               = 6

Therefore the value of p :

  $=T.DIST(-2.579143,6,TRUE)$

 = 0.020908803

The p value is 0.0209

$p< 0.05$

So we reject the null hypothesis and conclude that $\mu_1 < \mu_2$

7 0
3 years ago
What is dy/dx if y = (x2 + 2)3(x3 + 3)2? A. 3(x2 + 2)2(x3 + 3)2 + 2(x2 + 2)2(x3 + 3) B. 2x(x3 + 3)2 + 3x2(x2 + 2)3 C. 6x(x2 + 2)
Vlada [557]
We want to find \displaystyle{  \frac{dy}{dx}, for

            \displaystyle{ y=(x^2+2)^3(x^3+3)^2.

Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:

                                  (fg)'=f'g+g'f.

Thus,

 y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3

Answer: A)      3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3.



8 0
3 years ago
Write 125 as a product of primes. Use index notation when giving your answer.
Mnenie [13.5K]

Answer:

5^3

Step-by-step explanation:

125= 5*25

25=5*5

5 is a prime number and there are 3 of them so the answer in index notation will be 5^3

3 0
2 years ago
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