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alekssr [168]
3 years ago
11

0.6(y - 0.2) = 3 - 0.2(y - 1)

Mathematics
2 answers:
otez555 [7]3 years ago
8 0

Answer:

y=4.15

Step-by-step explanation:

0.6(y - 0.2) = 3 - 0.2(y - 1)

0.6y - 0.12 = 3 - 0.2y +0.2

        +0.12 =               +0.12

0.6y =3 - 0.2y +0.32

+0.2y = + 0.2y

0.8y/0.8 = 3.32/0.8

y= 4.15

inna [77]3 years ago
7 0

Answer: y= 4.15

You have to isolate the variable by itself

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Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 − 3 = x Square root of negative 2x plu
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Here I copy the steps and indicate where the error is.

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</span>

√[ - 2x + 1] - 3 = x

Square root of negative 2x plus 1 − 3 + 3 = x + 3 in this step she added 3 to each side, which is fine

<span> Square root of negative 2x plus 1 = x + 3 <span>she made the addtions => fine</span></span>

Square root of negative 2x plus 1 − 1 = x + 3 – 1 due to <span>plus 1 in inside the square root, this step will not help</span>

<span> Square root of negative 2 x = x + 2 <span>wrong! she cannot simplify - 1 that is out of the square root with +1 that is inside the square root
</span></span>


<span>Then, from here on all is wrong, but she made other additional mistakes.</span>

(Square root of negative 2 x)2 = (x − 4)2 −2x <span> the right side should be (x+2)^2 which is x^2 + 4x +4 not (x-4)^2 - 2x</span>

Later she made a mistake changing the sign of -8x to +8x


Those are the mistakes. Finally, the global error is that she should verify whether the found values satisfied the original equation.

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Read 2 more answers
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