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ad-work [718]
3 years ago
14

What is the positive solution to this equation 4x^2+12x=135

Mathematics
1 answer:
Stels [109]3 years ago
5 0

Answer:

answer for the equation is 6.75

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HELP I AM TIMED PLZZZZZZ!!!!!!!!!!!!!!!
otez555 [7]

Answer:

2/6 = d/84 d=24

Step-by-step explanation:

d=24

3 0
3 years ago
A cement walk 3 ft wide is placed around the outside of a rectangular garden plot that is 20ft by 30ft. Find the cost of the wal
Inessa05 [86]

Let us calculate the area of the walk.

Since the width of the walk is 3 feet, and the walk will be placed all the 4 sides,

Length of the plot including walk = 20 + (2 × 3) = 20 + 6 = 26 feet.

Breadth of the plot including walk = 30 + (2 × 3) = 36 feet.

Area of the plot including walk = 26 × 36 square feet.

Area of the plot = 20 × 30 square feet.

Area of the walk = (26 × 36) - (20 × 30)

= 936 - 600

= 336 square feet.

= \frac{336}{3(3)} square yards

= 37.3 square yards

Cost of the walk per square yard = $12.25.

Therefore, total cost of the walk = 12.25 × 37.3 = $456.92.

7 0
3 years ago
today a boat valued at $45,000.Thebvalue is expected to decrease at a rate of 8.5% each year.What is the value of the boat expec
Stels [109]

Current value of the boat = $45000

Rate at which the value decrease = 8.5%

Value decreased after 1 year = \frac{8.5}{100}\times45000=3825

Hence, value becomes = 45000-3825=41175

Value decreased after 2nd year =

\frac{8.5}{100}\times41175=3499.875

Hence, value becomes = 41175-3499.875=37675.125

Value decreased after 3 year =

\frac{8.5}{100}\times37675.125=3202.385

Hence, value becomes = 37675.125-3202.385=34472.74

So, value of the boat after 3 years becomes $34472.74

3 0
3 years ago
V=1/3 Bh, for h<br> A. h= 3V/B<br> B. h=B/3V<br> C. h=V/3B<br> D.h=3B/V
Basile [38]

Answer:

A. h=3v/b

Step-by-step explanation:

v=1/3bh

1) divide by b

v/b=1/3h

2) multiply reciprical

3v/b=h

h=3v/b

3 0
3 years ago
Travis jogged to his friend's house 10 miles away and then got a ride back home. It took him 2 hours longer to jog there than ri
spin [16.1K]

Using the relation between velocity, distance and time, it is found that his jogging rate was of 4.5 mph.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is <u>distance divided by time,</u> hence:

v = \frac{d}{t}

Jogging, his velocity was of v, while the time was of t + 2, for a distance of 10 miles, hence:

v = \frac{10}{t + 2}

Riding, his velocity was of 16, while the time was of t, also for a distance of 10 miles, hence:

v + 16 = \frac{10}{t}

Then, considering the first equation and replacing in the second:

\frac{10}{t + 2} + 16 = \frac{10}{t}

\frac{10}{t} - \frac{10}{t + 2} = 16

\frac{10t + 20 - 10t}{t(t + 2)} = 16

16t² + 32t - 20 = 0 -> t = 0.5.

Then his jogging rate in mph was:

v = \frac{10}{0.5 + 2} = 4.5

More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569

#SPJ1

8 0
2 years ago
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