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Mariana [72]
3 years ago
14

A force of 25 N acts on an object at an angle of 30 degrees above the horizontal. How much work does the force do if the object

slides 3 m?
Physics
1 answer:
8_murik_8 [283]3 years ago
3 0
We can find the x-component of the force vector, so Fx = 25N(cos30). Then, we can sub this into the work equation W = Fs or W = Fd. 
Therefore, W = (25N(cos30))(3m) = 64.95 J.
With sig figs, it is 60 J.
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kati45 [8]

Answer:

(A) 654.545 Kw

(B) 2.885\times 10^5kw

Explanation:

We have given resistance of the toaster R_1=2.2\times 10^{-2}ohm=0.022ohm

Resistance of nichrome heating element R_2=9.7ohm

Both the resistances are connected in series so same current will flow through the circuit

Potential difference across the toaster V = 120 volt

So current i=\frac{120}{0.022}=5454.5454A

(a) Power dissipated in toaster P=i^2R=5454.5454^2\times 0.022=654545.441W=654.545kw

(B) Power dissipated in heating element  P=i^2R=5454.5454^2\times 9.7=2.885\times 10^8W=2.885\times 10^5kw

5 0
4 years ago
What is the acceleration caused by gravity of the planet Earth?
Luda [366]
The general accepted value of acceleration due to gravity, g, is 9.81 m/s^2.

That is an approximation because being the acceleration of gravity due to the attraction of the earth its magnitude will depend on the distance from the point to the center of the planet Earth.

The value of g is determined by using the Newton's Universal Law of gravity:

F = G * m of Earth * m of body / (distance^2)

Wehre {G* m of Earth / (distance^2) } = g

G is a universal constant = 6.67 * 10 ^ -11 N*m^2 / kg^2

m of Earth = 5.98 * 10 ^ 24 kg 

distance = radius of Earth + height of the body

Given the the Earth is not a perfect sphere the radius varies. Also the height of the body varies.

If you take a mean radius of Earth of 6.37*10^6 m

you get

g = 6.67*10^-11 N*m^2/kg^2 * 5.98*10^24kg / (6.37*10^6 m)^2 = 9.83 m/s^2

Again, if you want a more precise value of g, you need to find the exact place where you are and then use the right r.



 
7 0
3 years ago
The rotational kinetic energy term is often called the kinetic energy in the center of mass, while the translational kinetic ene
weqwewe [10]

Answer:

C

Explanation:

The total kinetic energy is the sum of the kinetic energy in the center of mass (Rotational Kinetic energy) plus the kinetic energy of the center of mass( Translational Kinetic Energy).

The formula

K_{tot} = K_{t} +K_{r}  is applicable only when

The moment of inertia must be taken about an axis through the center of mass.

6 0
4 years ago
Read 2 more answers
Beginning 156 miles directly east of the city of Uniontown, a truck travels due south. If the truck is travelling at a speed of
timurjin [86]

Answer:

14.3

Explanation:

The distance s as a function of time can be written as:

s(t) = \sqrt{156^{2} + (31t)^2}

The rate of change is the derivative of d with respect to time:

\frac{ds}{dt} =\frac{961t}{\sqrt{156^{2}+(31t)^{2}}}

The time t when the track has been traveling for 81 miles is given by:

81 = 31t\\ t = \frac{81}{31}

Using t in the previous equation gives:

\frac{ds}{dt}(\frac{81}{31} ) =\frac{2511}{\sqrt{156^{2}+81^{2}}}=14.3

5 0
3 years ago
In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A r
Illusion [34]

Answer:

the weight of the rider is 493.53 N

Explanation:

Given the data in the question and as illustrated in the image below,

Tension T = 1900 N

the rider is moving at a constant speed so the net force in the horizontal direction will be 0

In the horizontal direction

F_{sailcos( 30° ) = Tcos ( 17° )

F_{sail = Tcos( 17° ) / cos( 30° )

F_{sail = 1900cos( 17° ) / cos( 30° )

F_{sail = 2098.07 N

Now, In the vertical direction,

F_{sail sin( 30° ) = W + T sin( 17° )

W = F_{sail sin( 30° ) - T sin( 17° )

W = 2098.07sin( 30° ) - 1900sin( 17° )

W = 1049.035 - 555.506

W = 493.53 N

Therefore, the weight of the rider is 493.53 N

7 0
3 years ago
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