Question

Your toaster has a power cord with a resistance of 2.2x10^−2 Ω connected in series with a 9.7 Ω nichrome heating element. The potential difference between the terminals of the toaster is 120 V.
1. How much power is dissipated in the power cord?
Pcord =_______ W
2. How much power is dissipated in the heating element?
Phe= ________ kW

Answer 1

Answer:

(A) 654.545 Kw

(B) $2.885\times 10^5kw$

Explanation:

We have given resistance of the toaster $R_1=2.2\times 10^{-2}ohm=0.022ohm$

Resistance of nichrome heating element $R_2=9.7ohm$

Both the resistances are connected in series so same current will flow through the circuit

Potential difference across the toaster V = 120 volt

So current $i=\frac{120}{0.022}=5454.5454A$

(a) Power dissipated in toaster $P=i^2R=5454.5454^2\times 0.022=654545.441W=654.545kw$

(B) Power dissipated in heating element  $P=i^2R=5454.5454^2\times 9.7=2.885\times 10^8W=2.885\times 10^5kw$