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topjm [15]
3 years ago
6

Your toaster has a power cord with a resistance of 2.2x10^−2 Ω connected in series with a 9.7 Ω nichrome heating element. The po

tential difference between the terminals of the toaster is 120 V.
1. How much power is dissipated in the power cord?
Pcord =_______ W
2. How much power is dissipated in the heating element?
Phe= ________ kW
Physics
1 answer:
kati45 [8]3 years ago
5 0

Answer:

(A) 654.545 Kw

(B) 2.885\times 10^5kw

Explanation:

We have given resistance of the toaster R_1=2.2\times 10^{-2}ohm=0.022ohm

Resistance of nichrome heating element R_2=9.7ohm

Both the resistances are connected in series so same current will flow through the circuit

Potential difference across the toaster V = 120 volt

So current i=\frac{120}{0.022}=5454.5454A

(a) Power dissipated in toaster P=i^2R=5454.5454^2\times 0.022=654545.441W=654.545kw

(B) Power dissipated in heating element  P=i^2R=5454.5454^2\times 9.7=2.885\times 10^8W=2.885\times 10^5kw

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Answer:

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Explanation:

The given parameters are;

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