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3 years ago

The most common example of a(n) ____ switched network is the conventional telephone system.

1 answer:

4 0

CIRCUIT Switched network has the conventional telephone system as the most common example.

Circuit switching is a method of implementing a telecommunication network in which two network nodes establish a dedicated communications channel or circuit through the network before the nodes may communicate. The circuit guarantees the full bandwidth of the channel and remains connected for the duration of the communication session by functioning as though the nodes were physically connected like an electrical circuit.

In a conventional telephone system, when a call is made from one telephone to another, switches within the the telephone exchanges create a continuous wire circuit between the two units for as long as the call lasts.

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A concave mirror has a focal length of 11 cm . What is its radius of curvature?

OverLord2011 [107]

Answer:

22cm

Explanation:

focal length = 11cm

radius of curvature,r = 2f

r= 2 x 11

r=22cm

6 0

3 years ago

This is one of the four planets Mercury,Venus,Earth,and Mars, whose orbits lie nearest the Sun

galben [10]

Answer:

Mercury

Explanation:

Mercury is the closest planet to the sun followed be Venus. Though Mercury is the closest Venus is actually the hotest planet

6 0

3 years ago

Read 2 more answers

Suppose you are drinking root beer from a conical paper cup. The cup has a diameter of 10 centimeters and a depth of 13 centimet

sveta [45]

Answer:

The level of the root beer is dropping at a rate of 0.08603 cm/s.

Explanation:

The volume of the cone is :

$V=\frac {1}{3}\times \pi\times r^2\times h$

Where, V is the volume of the cone

r is the radius of the cone

h is the height of the cone

The ratio of the radius and the height remains constant in overall the cone.

Thus, given that, r = d / 2 = 10 / 2 cm = 5 cm

h = 13 cm

r / h = 5 / 13

r = {5 / 13} h

$V=\frac {1}{3}\times \frac {22}{7}\times ({{{\frac {5}{13}\times h}}})^2\times h$

$V=\frac {550}{3549}\times h^3$

Also differentiating the expression of volume w.r.t. time as:

$\frac {dV}{dt}=\frac {550}{3549}\times 3\times h^2\times \frac {dh}{dt}$

Given: $\frac {dV}{dt}$ = -4 cm³/sec (negative sign to show leaving)

h = 10 cm

So,

$-4=\frac{550}{3549}\times 3\times {10}^2\times \frac {dh}{dt}$

$\frac{55000}{1183}\times \frac {dh}{dt}=-4$

$\frac {dh}{dt}=-0.08603\ cm/s$

The level of the root beer is dropping at a rate of 0.08603 cm/s.

3 0

3 years ago

A space shuttle sits on the launch pad for 2.0 minutes, and then goes from rest to 4600 m/s in 8.0 minutes. Treat its motion as

SpyIntel [72]

Answer:

a.) a = 0 ms⁻²

b.) a = 9.58 ms⁻²

c.) a = 7.67 ms⁻²

Explanation:

a.)

Acceleration (a) is defined as the time rate of change of velocity

$a = \frac{v_{2} - v_{1} } {t}$

Given data

Final velocity = v₂ = 0 m/s

Initial velocity = v ₁ = 0 m/s

As the space shuttle remain at rest for the first 2 minutes i.e there is no change in velocity so,

a = 0 ms⁻²

b.)

Given data

As the space shuttle start from rest, So initial velocity is zero

Initial velocity = v₁ = 0 ms⁻¹

Final velocity = v₂ = 4600 ms⁻¹

Time = t = 8 min = 480 s

By the definition of Acceleration (a)

$a = \frac{v_{2} - v_{1} } {t}$

$a = \frac{4600 - 0 } {480}$

a = 9.58 ms⁻²

c.)

Given data

As the space shuttle is at rest for first 2 min then start moving, So initial velocity is zero

Initial velocity = v₁ = 0 ms⁻¹

Final velocity = v₂ = 4600 ms⁻¹

Time = t = 10 min = 600 s

By the definition of Acceleration (a)

$a = \frac{v_{2} - v_{1} } {t}$

$a = \frac{4600 - 0 } {600}$

a = 7.67 ms⁻²

8 0

3 years ago

If you and a friend are standing at opposites ends of a gymnasium and one of you claps, will the other hear the clap at the same

34kurt

Answer:

No. Your friend will not hear the clap when he/she sees it.

Explanation:

It takes time for sound waves to go through a large area. It takes longer if people are in the area rather than it is empty.

3 0

3 years ago