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V125BC [204]
3 years ago
6

On a coordinate plane, a parabola opens down. It has an x-intercept at (negative 5, 0), a vertex at (negative 1, 16), a y-interc

ept at (0, 15), and an x-intercept at (3, 0).
The function f(x) = –x2 − 2x + 15 is shown on the graph. What are the domain and range of the function?

The domain is all real numbers. The range is {y|y < 16}.
The domain is all real numbers. The range is {y|y ≤ 16}.
The domain is {x|–5 < x < 3}. The range is {y|y < 16}.
The domain is {x|–5 ≤ x ≤ 3}. The range is {y|y ≤ 16}
Mathematics
2 answers:
Ivenika [448]3 years ago
5 0

Answer:

Its C

Step-by-step explanation:

took the test

Zanzabum3 years ago
4 0

Answer:

the domain is xl-5<×< 3 is the range of 16

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Can someone help me pls?
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Answer:

x = 17.2

Step-by-step explanation:

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Find all of the zeros of the function f(x)=x^3-17x^2+81x-65
viktelen [127]
A graph shows the function can be factored as
  f(x) = (x -1)((x-8)² +1)

There is one real root and there are two complex roots. The latter can be found from the vertex form factor:
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The zeros of the function are {1, 8-i, 8+i}.

4 0
3 years ago
the price of three different bags of cat food are shown in the table to the right. Which bags has the lowest price per pound? si
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5 0
3 years ago
The midpoint of AB is M(-1, –4). If the coordinates of A are (-3, -7), what are
quester [9]

Answer:

<h3>            B(1, -1)</h3>

Step-by-step explanation:

If M(-1, 4) is midpoint of AB then:

x_M-x_A=x_B - x_M\qquad\quad\ \wedge\qquad y_M-y_A=y_B - y_M\\\\ -1-(-3)=x_B-(-1)\qquad\wedge\qquad -4-(-7)=y_B -(-4)\\\\ -1+3=x_B+1\qquad\qquad\wedge\qquad\ \ -4+7=y_B+4 \\\\ {}\qquad x_B=1\qquad\qquad\wedge\qquad\qquad \ y_B=-1

5 0
3 years ago
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