Question

Mike ate 1 3 of a bag of peanuts at the game, and on the way home he ate 1 3 of what was left. How much of the bag of peanuts did mike eat on the way home?

Answer 1

Answer:

$\frac{2}{9}$

Step-by-step explanation:

Given that

Mike ate = $\frac{1}{3}$ of peanuts bag

And when he is on the way to home he ate the remaining of $\frac{1}{3}$ peanuts bag

So, the remaining peanuts is

= 1 - $\frac{1}{3}$

= $\frac{2}{3}$

So, the total number of peanuts he eat on the way to home is

= $\frac{1}{3}\times\frac{2}{3}$

= $\frac{2}{9}$

We simply multiplied the remaining and available peanuts bag ratio so that the correct ratio could come