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julia-pushkina [17]

3 years ago

8

Mike ate 1 3 of a bag of peanuts at the game, and on the way home he ate 1 3 of what was left. How much of the bag of peanuts di

d mike eat on the way home?

1 answer:

Black_prince [1.1K]3 years ago

3 0

Answer:

$\frac{2}{9}$

Step-by-step explanation:

Given that

Mike ate = $\frac{1}{3}$ of peanuts bag

And when he is on the way to home he ate the remaining of $\frac{1}{3}$ peanuts bag

So, the remaining peanuts is

= 1 - $\frac{1}{3}$

= $\frac{2}{3}$

So, the total number of peanuts he eat on the way to home is

= $\frac{1}{3}\times\frac{2}{3}$

= $\frac{2}{9}$

We simply multiplied the remaining and available peanuts bag ratio so that the correct ratio could come

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What is the component form of the vector that translates the top house figure to the

Readme [11.4K]

The component form of the vector that translates the top house figure to the bottom house figure is (6, -4).

<h3>What is the vector component form?</h3>

The component form of a vector is known to be depicted as < x, y >.

Note that:

x - tells the distance or how far to the right or left, a vector is known or seen to be going.

y - tells the distance or how far to the upper part or downward a vector is known or seen to be going.

From the question and looking at the image attached, we were able to obtain (-4,4) and (2, 0)

So:

⇒ (-4,4) --------(-4+6)(4-4)-------(2,0)

⇒ (6,-4)

Hence, The component form of the vector that translates the top house figure to the bottom house figure is (6, -4).

Learn more about vector from

brainly.com/question/25705666

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8 0

2 years ago

Please help asap, I'm so confused lol.

Sladkaya [172]

Answer: $450

Step-by-step explanation:

We can form an equation representing the problem. The question is essentially asking 60% of what is equal to $270. If we define that what as a variable 'x', we get the following:

$\frac{60}{100} *x=270$

$\frac{60x}{100} =270$

Multiply both sides by 100:

$\frac{60x}{100} *100=270*100$

$60x=27,000$

Divide both sides by 60 to solve for the value of 'x':

$x=\frac{27,000}{60} =450$

Answer is 450 bucks

We can check this answer by taking 60% of $450. In principal, this should return the discount of $270.

$\frac{60}{100} *450=270$

Yup, it checks out

8 0

2 years ago

Read 2 more answers

The value of q varies directly withp2,andq=16whenp=2.What is the value of q whenp=12?

lisov135 [29]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------$

$\bf \textit{q varies directly with p}^2\qquad q=kp^2
\\\\\\
\textit{we also know that }
\begin{cases}
q=16\\
p=2
\end{cases}\implies 16=k2^2\implies \cfrac{16}{2^2}=k
\\\\\\
4=k\qquad therefore\qquad \boxed{q=4p^2}
\\\\\\
\textit{when p = 12, what is \underline{q}?}\qquad q=4(12^2)$

7 0

3 years ago

37. Socks. In your sock drawer you have 4 blue socks, 5 grey socks, and 3 black ones. Half asleep one morning, you grab 2 socks

mihalych1998 [28]

Answer:

a) $\frac{1}{22}$

b) $\frac{7}{22}$

c) $\frac{5}{11}$

d) $\frac{35}{66}$

Step-by-step explanation:

Given,

Number of blue socks = 4,

Grey socks = 5,

Black socks = 3,

Total socks = 4 + 5 + 3 = 12,

Ways of choosing any 2 socks = $^{12}C_2$

$=\frac{12!}{2!10!}$

$=\frac{12\times 11}{2}$

$=6\times 11$

= 66,

a) Ways of choosing 2 blue socks = $^3C_2$

= 3,

Since, $\text{Probability}=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

Thus, the probability of selecting 2 blue socks = $\frac{3}{66}=\frac{1}{22}$

b) Ways of choosing 2 shocks, non of them are grey socks = $^7C_2$

$=\frac{7!}{2!5!}$

$=7\times 3$

$=21$

Thus, the probability of selecting no grey socks = $\frac{21}{66}$

$=\frac{7}{22}$

c) ways of selecting atleast 1 black sock = ways of selecting 1 black sock + ways of selecting 2 black socks

$=^3C_1\times ^9C_1+^3C_2$

$=3\times 9 + 3$

$=27 + 3$

= 30,

Thus, the probability of selecting at least 1 black sock = $\frac{30}{66}$

$=\frac{5}{11}$

d) Ways of selecting a green sock = $^5C_1\times ^7C_1$

= 35,

Thus, the probability of selecting a green sock = $\frac{35}{66}$

3 0

3 years ago

(5 1/8 - 3/4)÷-1 3/4 what's the answer?

Mumz [18]

The answer to this problem would be -2.5

5 0

3 years ago