Sum of 2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so
x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4
the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=

for x²-4x+16=0
x=

x=

x=

x=

x=

x=

the roots are
x=-4 and 2+2i√3 and 2-2i√3
I hope this helps you
6. (-7).a^2+4.b^1+7
-42.a^6.b^8
<h2>GOOD LUCK CHUCK :)))))))))</h2>
Answer:
the teachers would have 24 students per teacher. 10 students per tutor. There would need to be 11 tutors
Step-by-step explanation:
each tutor would have 10 students then if you do 11 times 10 you get 11
(hope this helps can I pls have brainlist (crown)☺️)
P=18
l=5 cm greater than the width
w=5 less than the length
USE YOUR NUMBER SENSE!!! - just plug in different number below 4 to figure out the width
3=w 3+5=8 8+8=16+6=22 WILL NOT WORK
2=w 2+5=7 7+7=14 14+2+2= 18 WE HAVE A WINNER!!!!
FInal Answer: width: 2 cm and length: 7 cm