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julia-pushkina [17]
3 years ago
8

Mike ate 1 3 of a bag of peanuts at the game, and on the way home he ate 1 3 of what was left. How much of the bag of peanuts di

d mike eat on the way home?
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
3 0

Answer:

\frac{2}{9}

Step-by-step explanation:

Given that

Mike ate = \frac{1}{3} of peanuts bag

And when he is on the way to home he ate the remaining of \frac{1}{3} peanuts bag

So, the remaining peanuts is

= 1 - \frac{1}{3}

= \frac{2}{3}

So, the total number of peanuts he eat on the way to home is

= \frac{1}{3}\times\frac{2}{3}

= \frac{2}{9}

We simply multiplied the remaining and available peanuts bag ratio so that the correct ratio could come

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The GCF stands for greatest common factor. To represent a sum by its GCF we need to use the distributive property and we need to first find the GCF of the numbers. Let's break each number by its factors:

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