3 years ago

Someone please help me with this !!!

1 answer:

7 0

It is the first one, so where it is marked is already correct

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AlladinOne [14]

The answer is c, 4 inches
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3 years ago

stich3 [128]

Answer:

4.6%.

Step-by-step explanation:

The probability that a can of paint contains contamination(C) is 3.23%

P(C)=3.23%

The probability of a mixing(M) error is 2.4%.

P(M)=2.4%

The probability of both is 1.03%.

$P(C \cap M)=1.03\%$

We want to determine the probability that a randomly selected can has contamination or a mixing error. i.e. $P(C \cup M)$

In probability theory:

$P(C \cup M) = P(C)+P(M)-P(C \cap M)\\P(C \cup M)=3.23+2.4-1.03\\P(C \cup M)=4.6\%$

The probability that a randomly selected can has contamination or a mixing error is 4.6%.

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3 years ago

Afina-wow [57]

${x50506}^{?}$

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3 years ago

Wewaii [24]

Factor 11 x^2 y^2 out of both the numerator and the denominator to get 2(11 x^2 y^2)/11x^2 y^2, which is clearly equal to 2.

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3 years ago

GenaCL600 [577]

68 is the answer........

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3 years ago