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MrRissso [65]
3 years ago
10

Someone please help me with this !!!

Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0

It is the first one, so where it is marked is already correct

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5/12 x 16 2/3<br><br> Im lazy :p thank you for helping though
polet [3.4K]
The answer is 125/18. decimal form would be 6.94 (repeating) lol
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8 0
2 years ago
Can someone please help me answer this Math problem?
kap26 [50]

Answer:

2√2.

Step-by-step explanation:

We use the Pythagoras Theorem:

x^2 = 2^2 + 2^2

x^2 =  8

x = √8

= 2√2.

4 0
2 years ago
Help help help help help help help
sdas [7]
It would be 120.

Look at the first column, 40. It’s basically multiplication and you can just use a calculator.

For example, 40 x 1 = 40,
And if you looks the second column, it’s being multiplied by 2. Which would be 40 x 2, you just have to multiply 3 x 40 which is 120.

Sorry for my english

7 0
2 years ago
What are the number of integral solutions of the equation 2x+2y+z=20 such that x&gt;=0 , y&gt;=0 , z&gt;=0?
zaharov [31]
2x+2y+z=20\\&#10;z=\dfrac{20}{2x+2y}\\&#10;z=\dfrac{10}{x+y}

Now, for z to be an integer, the sum x+y must be a divisor of 10. 
It has to be a positive divisor since z≥0. Also x≠y.

x+y=1 \\&#10;x=1-y\\&#10;
x≥0 and y≥0 so y can be equal to either 0 or 1. There are 2 solution in this case.

x+y=2\\&#10;x=2-y\\
In this case, y can be equal to 0,1, or 2, but for y=1 ⇒ x=1, so there are two solutions.

x+y=5\\&#10;x=5-y
y can be 0,1,2,3,4 or 5 - 6 solutions

x+y=10\\&#10;x=10-y
y can be 0,1,2,3,4,5,6,7,8,9,10, but for y=5 ⇒ x=5, so 10 solutions.

2+2+6+10=20 solutions in total.
6 0
3 years ago
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