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zaharov [31]
3 years ago
9

every prime number greater than 10 has a digit in the ones place that is included in which set of numbers below?

Mathematics
1 answer:
stich3 [128]3 years ago
8 0
So we can start with the full of possibilities and eliminate them one by one.

The full set is {0,1,2,3,4,5,6,7,8,9}.

Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:

{1,3,5,7,9}

We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.

{1,3,7,9}

We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:

{1,3,7,9} as our answer.
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Adena used a qualateral in her ary design. The quadrlateral has no sides ,and only one pair of opposite sides parallel what shap
Radda [10]

Answer: The quadrilateral used here is a trapezium.




3 0
3 years ago
What is greater 95% or 1 1/2​
Snowcat [4.5K]
1 1/2 cause your getting half not just sum
4 0
3 years ago
If n(A)=26, n(B)=41, and n(A ∩ B)=8, find n(A ∪ B).
miskamm [114]

n (AUB) = 59

Step-by-step explanation:

n(A U B) = n(A) + n(B) -n(A intersection B)

= 26+ 41- 8

= 59

8 0
3 years ago
What is the factored form of this expression? 4t2 − 27t + 18
seraphim [82]

Answer:

(4t − 3) (t − 6)

Step-by-step explanation:

Using AC method:

Given a quadratic ax² + bx + c, find factors of ac that add up to b.  Divide those factors by a and reduce.  The denominators become the coefficients and the numerators become the constants.

Here, a = 4, b = -27, and c = 18.

ac = 4 × 18 = 72

Factors of 72 that add up to -27: -3 and -24

Divide factors by a: -3/4 and -24/4

Reduce: -3/4 and -6/1

So the factored expression is:

(4t − 3) (t − 6)

5 0
3 years ago
Points A, B, and C are collinear. Point B is between A and C. Find the length indicated. AB= 5x-15, BC=3x-5, and AC=28. Find AB
katrin2010 [14]

Answer: AB is 15

Step-by-step explanation: First, you need to draw a picture and label the parts of the line: AB=5x-15; BC= 3x-5; AC =28. Because of the segment addition postulate, you set the equation to be 5x-15+3x-5=28. Then you solve:

5x-15+3x-5=28

Add like terms:

8x-20=28

Add 20 to both sides

8x=48

Divide by 8

x=6

Now, you need to find the measure of AB, so you plug the 6 into the x variable for 5x-15

5(6)-15

30-15

AB=15

4 0
2 years ago
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