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zaharov [31]
3 years ago
9

every prime number greater than 10 has a digit in the ones place that is included in which set of numbers below?

Mathematics
1 answer:
stich3 [128]3 years ago
8 0
So we can start with the full of possibilities and eliminate them one by one.

The full set is {0,1,2,3,4,5,6,7,8,9}.

Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:

{1,3,5,7,9}

We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.

{1,3,7,9}

We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:

{1,3,7,9} as our answer.
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Sodium-24 has a half-life of 15 hours. how many grams of a 900 g sample will remain after 90 hours
raketka [301]

Answer: Option 'B' is correct.

Step-by-step explanation:

Let the initial concentration be

N_0=900\ g

Let concentration after t= 90 hours be N

Since we have given that Sodium-24 has a half life of 15 hours i.e.

t_{\frac{1}{2}}=15

So, According to question,

\text{ Number of half lives }=\frac{t}{t_{\frac{1}{2}}}\\\\\text{ Number of half lives }=\frac{90}{15}\\\\\text{ Number of half lives }=6

As we know that

\frac{N}{N_0}=(\frac{1}{2})^n\\\\N=N_0\times (\frac{1}{2})^n\\\\N=900\times (\frac{1}{2})^6\\\\N=\frac{900}{64}\\\\N=14.0625\ g

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4 0
4 years ago
A banana bread recipe that makes 444 loaves calls for 121212 bananas. If you are making 242424 loaves, how many bananas do you n
rjkz [21]
888 bananas, you can uses ratio or proportion to solve it; 444/121212:X/242424, 444*242424 and divide that by 121212 and you get 888. Hope this helps! :)
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3 years ago
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3 years ago
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emmainna [20.7K]

Answer:

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Step-by-step explanation:

Let s be the shaded area and u be the unshaded area, then we know that

(1).  \frac{s}{u}=\frac{3}{2}

and

(2).   s+u=(2x+15)

We solve for u in the first equation and get:

u=\frac{2}{3}s

and put this into the second equation and get:

s+\frac{2}{3}s=(2x+15)

s(1+\frac{2}{3} )=(2x+15)

s(\frac{5}{3}  )=(2x+15)

\boxed{s=\frac{3}{5} (2x+15)}

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3 years ago
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Answer:

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Step-by-step explanation:

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