I think its 15+y or 15y im not surw
In order to solve or know the probability of having 2 girls
and 2 boys, assumed that a girl is as likely as a girl at each birth, pascal’s
triangle will be likely used. And we will be referring to the line 4 of pascal’s
triangle, which was 1 4 6 4 1. Then it
will look like this: 1 = 4 girls; 4 = 3 girls & 1 boy; 6 = 2 girls & 2
boys; 4 = 3 boys & 1 girl; 1 = 4 boys. And now for the solution in order to
get the probability of having 2 girls and 2 boys is to divided into the sum of 1+4+6+4+1.
Answer:
502.4
Step-by-step explanation:
Use tangent because the side you know and the side with x are both legs.
Do 203/tan(22) and you should get your awnser.
You devide by 203 because the rule is opposite over ajacent and 203 is the opposite side.
Answer: He would earn $14
Step-by-step explanation: Since Sam had 11 games but only 9 of them were working just take 11 - 9 which = 2 then take 7 x 2 to get $14
Hope this helps
.21 as a percentage is 21%
You can divide 7.98 by 21 then multiply by 100 which gives you an answer of 38.
Hope this helps :)
