What is the perimeter of the triangle expressed as a polynomial?

1 answer:

8 0

Add the polynomials together:
(5x-2)+(2x-3)+(4x+3)
Combine like terms:
(5x+2x+4x) + (-2+-3+3) = 11x-2

So the answer is D.

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Please help I’ll mark brainliest if correct please explain also

adell [148]

Answer:

2/5

Step-by-step explanation:

5x+6y=11

as we have to find x coordinate

while y coordinate 3/2 is already given in question

so only put value of y coordinate in given equation to get x coordinate value

5x+6y=11

5x+6*(3/2)=11

5x+3*3=11

5x+9=11

5x=11-9

5x=2

x=2/5

6 0

3 years ago

PLS HELP<br> THE SQUARE ROOT OF -17

jek_recluse [69]

Answer:

i√17 ≈ 4.123106i

Step-by-step explanation:

The square root of a negative number is "i" times the square root of its absolute value. It is an imaginary number.

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i is generally the symbol used for √(-1). In some fields, such as electrical engineering, where i has a different meaning, the symbol j may be used instead.

6 0

2 years ago

Please solve all with explanation

garri49 [273]

Answer:

1. $\frac{x^2}{y^8}$

2 a) $\frac{-49}{2}$

b) 0

3. x = 10

Step-by-step explanation:

$(\frac{x^{-3}y^4}{x^{-2}})^{-2}\\({x^{-3+2}y^4})^{-2}\\({x^{-1}y^4})^{-2}({x^{-1*-2}y^{4*-2})= \frac{x^2}{y^8}$

2. a)

$2 [(\frac{-1}{4}) -12 (-1)^2] - 5[24 +2 (-12)]^2\\2[(\frac{-1}{4}) -12] - 5[24 -24]^2\\2 * [(\frac{-1}{4}) -12] -0\\\frac{-49}{2}$

$-a^2b^2 - 3a^3b^2\\-\frac{1}{9}*1 - 3 * \frac{-1}{27} *1\\-\frac{1}{9} + \frac{1}{9}\\0$

$\frac{3}{4}x + \frac{5}{6} = 5x -\frac{125}{3} \\\frac{5}{6} + \frac{125}{3} = 5x - \frac{3}{4}x\\\frac{5+250}{6} = \frac{20x -3x}{4}\\\frac{255}{6} = \frac{17x}{4}\\x = 10$