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andreev551 [17]
3 years ago
6

Which of the following rational functions is graphed below?

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

D.

Step-by-step explanation:

x -> 0   y -> 0

Vertical asymptote: x = 3, x = 4    (x-3)=0 and (x-4) = 0

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Point B lies between points A and C, and all three points lie on point AC, which of the following is not true? A. Point B lies o
loris [4]

Answer:

C. Point A lies on ray BC

Step-by-step explanation:

Points A and C can be connected by a segment which would be a measure of the distance between the points. Locating point B between AC, makes the three points lying on segment AC.

A ray extends from a point to infinity, a line extend to infinity on both sides, while a segment is known to have two endpoints. Therefore, points AC are the end points of the segment AC, and point B between this segment confirms that point B lies on the segment AC. Therefore, Point A lies on ray BC is not correct.

8 0
3 years ago
Add 3x4 - 7x3 + 12x - 9
PolarNik [594]

Answer:

i also need

Step-by-step explanation:

8 0
3 years ago
Pls help it’s due today
IgorLugansk [536]

Answer: y = 2/1x + 2

Step-by-step explanation:

A slope of 2 means rising 2 and run 1 on a graph. This would make x = 2/1. The + 2 allows the line to pass through (0,2) and therefore it will also pass through (-2,-2).

4 0
3 years ago
A highway between points A and B has been closed for repairs. An alternative route between there two locations is to travel betw
Kitty [74]

Answer:

The value of Y is 24 km and distance from A to C to B is AC+Y=18+24=42 km

Step-by-step explanation:

Given that A highway between points A and B has been closed for repairs. An alternative route between there two locations is to travel between A and C and then from C to B. we have to find the value of Y and the total distance from A to C to B. Let AB=Z

In ΔBCD and ΔABD

∠BCD=∠ABD       (∵each 90°)

∠D=∠D                 (∵common)

By AA similarity, ΔBCD~ΔABD

∴ their corresponding sides are proportional

\frac{Y}{Z}=\frac{X}{40}=\frac{40}{18+X}

Comparing last two terms, we get

\frac{X}{40}=\frac{40}{18+x}

⇒ X(18+X)=1600

⇒ 18X+X^2=1600

⇒ X^2+18X-1600=0

⇒ X^2-32X+50X-1600=0

⇒ (X-32)(X+50)=0

Hence, the roots are X=32, -50

X=-50 not possible as distance can never negative.

Hence, X=32 km

By applying Pythagoras theorem in ΔBCD we get

BD^2=BC^2+CD^2

40^2=Y^2+32^2

⇒ Y^2=1600-1024=576

⇒ Y=\sqrt576=24km

Hence, the value of Y is 24 km and the distance from A to C to B is AC+Y=18+24=42 km




5 0
3 years ago
What is the answer to #5 math will give brainliest
pav-90 [236]

Answer:

Vertex is (0,6)  -y axis   D = (-infinite,+infinite)  R = [6,-infinite)

Step-by-step explanation:


5 0
4 years ago
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