The slope is given as m = 7m=7 and the yy-intercept as b = - \,4b=−4. Substituting into the slope-intercept formula y = mx + by=mx+b, we have
since m=7 and b=-4, we can substitute that into the slope-intercept form of a line to get y=mx+b → y=7x-4
The slope is positive thus the line is increasing or rising from left to right, but passing through the yy-axis at point \left( {0, - \,4} \right)(0,−4).
Step-by-step explanation:
Do the area of the circle as a whole minus (72/360 x radius^2) and then minus the other grey area.
Answer:
5x^4 -7x^3-5x^2+5x+1
Step-by-step explanation:
Hey!
You would just add all the numbers up, and by making sure that you combine all like terms. In this case it is just 1-0 = 1 and so the solution would be the same as your question but with a 1 and you would get rid of the -0.
Hope this helps!