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12345 [234]
3 years ago
9

Answer #5,6,7,8,9,10

Mathematics
2 answers:
MatroZZZ [7]3 years ago
7 0
5)\ -2\times\frac{3}{7}=-\frac{2\times3}{7}=-\frac{6}{7}\\\\6)\ -2\frac{2}{3}\times4\frac{1}{10}=-\frac{8}{3}\times\frac{41}{10}=-\frac{4}{3}\times\frac{41}{5}=-\frac{164}{15}=-10\frac{14}{15}\\\\7)\ -2\frac{1}{5}\times(-1\frac{3}{4})=-\frac{11}{5}\times(-\frac{7}{4})=\frac{77}{20}=3\frac{17}{20}\\\\8)\ -1\frac{1}{4}\times9=-\frac{5}{4}\times9=-\frac{45}{4}=-11\frac{1}{4}\\\\9)\ -1\frac{5}{7}\times(-2\frac{1}{2})=-\frac{12}{7}\times(-\frac{5}{2})=\frac{6}{7}\times\frac{5}{1}=\frac{30}{7}=4\frac{2}{7}

1)\ -2\frac{3}{8}\times2\frac{1}{2}=-\frac{19}{8}\times\frac{5}{2}=-\frac{95}{16}=-5\frac{15}{16}
777dan777 [17]3 years ago
6 0

Answer:

Step-by-step explanation:

-5 5/16

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Find the common difference for the following sequence and fill in the missing terms. Show all calculations. 2, 13, 24, 35, __, _
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Step-by-step explanation:

Hey there!

Given sequences are; 2 , 13 , 24 , 35 , _ , _ .

Now,

Common difference (d) = 2nd term - 1st term. = 13-2 = 11

When we subtract 1st term from 2nd term we find 11 and when we subtract 2nd term from 3rd term we get 11. This means our common difference is 11.

Now, let's find the nrh term of the sequence.

nth term= a1 + (n-1)d ( <em>a1= 1st term, d= common</em> <em>difference</em>)

nth = 2+ (n-1) 11

= 2 + 11n - 11

= 11n - 9

Let's check if we have got nth term correct.

a1= 1*11 - 9 = 2

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So, we got our nth term.

Let's find remaining sequence.

a5= 5*11 - 9 = 46.

a6= 6*11 - 9 = 57.

Therefore, the remaining terms are : 46 and 57.

<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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What is the result of subtracting the second equation from the first?
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This is the answer with explanation

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Step-by-step explanation:

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Step-by-step explanation:

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