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jasenka [17]
3 years ago
14

50) The first year Beth worked she earned n. The second year she earned 500 more than twice what she made the first year. The th

ird year she earned 500 less than twice what she made the second year. Which correctly expresses the amount she made the third year?
Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0

Answer:

2n+500+2(2n+500) -500

Step-by-step explanation:

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5x+5<-3 inecuaciones ​
iris [78.8K]

Answer:

x<-8/5

Step-by-step explanation:

7 0
3 years ago
Find the value of h(x) = -3x – 12 when x = -2? Show work
7nadin3 [17]

Answer:

-6

Step-by-step explanation:

h(x) = -3x – 12 becomes h(-2) =  -3(-2) – 12 = -6

7 0
3 years ago
Nine less than two-thirds a number is greater than twenty-five. Which inequality best represents the situation?
Rudik [331]

To solve this problem you must apply the proccedure shown below:

1. First, you must understand the information given in the exercise. You have that: nine less than two-thirds a number is greater than twenty-five.

2. Let's call x to the number mentioned above. You have that "nine less than two-thirds a number" means a substraction and " is greater than twenty-five" can be expressed with the symbol >.

Therefore, you have that the answer is:

9-2/3(x)>25


7 0
3 years ago
Estimate at 15% tip on a dinner bill of $39.84 by first rounding the bill amount to the nearest $10
Burka [1]

Answer:

$6

Step-by-step explanation:

$39.84≈$40

tip=15% of 40=0.15×40=$6.00

3 0
3 years ago
Arsenic is a compound that occurs naturally in very low concentrations. Arsenic blood concentrations in healthy adults are Norma
DENIUS [597]

Answer:

0.7325 to 5.6675 ug/dl

Step-by-step explanation:

The middle 90% will be 45% above the mean and 45% below the mean.  This means

0.5-0.45 = 0.05 and

0.5+0.45 = 0.95

We use a z table.  Look in the cells; find the values as close to 0.05 and 0.95 as we can get.

For 0.05, we have 0.0505 and 0.0495; since these are equidistant from 0.05, we use the value between them.  0.0505 is z=-1.64 and 0.0495 is z=1.65; this gives us z=-1.645.

For 0.95, we have 0.9495 and 0.9505; since these are equidistant from 0.95, we use the value between them.  0.9495 is z = 1.64 and 0.9505 is z=1.65; this gives us z = 1.645.

Now we use our z score formula,

z=\frac{X-\mu}{\sigma}

Our two z scores are 1.645 and -1.645; our mean, μ, is 3.2; and our standard deviation, σ, is 1.5:

1.645=\frac{X-3.2}{1.5}

Multiply both sides by 1.5:

1.5(1.645)=\frac{X-3.2}{1.5}\times 1.5\\\\2.4675 = X-3.2

Add 3.2 to each side:

2.4675+3.2 = X-3.2+3.2

5.6675 = X

-1.645=\frac{X-3.2}{1.5}

Multiply both sides by 1.5:

1.5(-1.645)=\frac{X-3.2}{1.5}\times 1.5\\\\-2.4675=X-3.2

Add 3.2 to each side:

-2.4675+3.2 = X-3.2+3.2

0.7325 = X

Our range is from 0.7325 to 5.6675.

5 0
3 years ago
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