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zimovet [89]
3 years ago
15

What is gonorrhea ?????????

Health
1 answer:
anastassius [24]3 years ago
6 0
Gonorrhea is basically a STD. 
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The risk of developing hypertension, heart disease, and a stroke can be
Basile [38]

Answer:

The risk of developing hypertension, heart disease, and a stroke can be

reduced through regular exercise and <u>proper</u><u> </u><u>sleeping</u><u> </u><u>habits</u><u>.</u>

3 0
3 years ago
1. A muscular system essential because it allows our bones to? A. Strengthen B. Contract C. Lengthen D. Move
QveST [7]
Your answer is b idk why they want me to put 20 characters for this

4 0
3 years ago
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John Snow, in Snow on Cholera: A. established postulates for transmission of infectious disease. B. was the father of modern bio
SCORPION-xisa [38]

Answer: (C) Was an English anesthesiologist who used natural experiments.

Explanation:

 John snow was an English anesthesiologist and he accomplishment in the anesthesia, medicine and in the epidemiology.

Dr john snow set up the series for using the natural experiments. He is also known as the father of the modern epidemiology.

He basically believe that the sewage dump into the rivers near the town can cause the cholera outbreak. In 1854, he investigated the reason of out break and also proves his theory in the Soho, London. He also leader of the development of the medical hygiene and the anesthesia.

7 0
3 years ago
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Two parents who are heterozygous for type A blood and have sickle cell trait have children.
GuDViN [60]

This question is incomplete, but here is the complete question below.

In humans , blood type is a result of multiple alleles: I^{A}, I^{B}, i^{o}.

A few simple rules of blood type genetics are that:

I^{A} is dominant over i^{o}

I^{B} is dominant over i^{o}, and

I^{A}I^{B} are codominant

Two plants who are heterozygous for type A blood and have sickle cell trait have children. Answer the following questions:

a. What is the genotype of the parents?

b. What are the genetic make ups of all the possible gametes they can produce.

c. Complete the dihybrid Punnet square to determine the frequency of the different phenotypes in the offspring.

(NOTE: Consider blood type and normal versus mutant hemoglobin in the various phenotypes.)

Answer:

a) I^{A}i^{o}AS

b) I^{A}A,I^{A}S,i^{o}A,i^{o}S

c) The dihybrid table is shown in the explanation below and the frequency of the different phenotypes of the offspring are in the ratio of 3:6:3:1:2:1

Explanation:

a)

From the question the genotype of the parents can be determined:

Given that Two parents are heterozygous for  type  A and have sickle cell trait.

∴ heterozygous for  type  A will be  = I^{A}i^{o} &

heterozygous for having sickle cell traits = AS

Therefore, the traits can be determined the genotype of the parents can be determined as: I^{A}i^{o}AS

b)

the genetic make ups of all the possible gametes they can produce can be determined if the parent are self crossed.

If I^{A}i^{o}AS self crossed, we have:

                I^{A}                 i^{o}

A              I^{A}A               i^{o}A

S              I^{A}S                i^{o}S

∴ The genetic makeups of all the possible gametes they can produce are:

I^{A}A, I^{A}S, i^{o}A, i^{o}S

c)

Below shows the dihybrid Punnet square and  the frequency of the different phenotypes in the offspring

               I^{A}A               I^{A}S                    i^{o}A                 i^{o}S

I^{A}A     I^{A}I^{A}AA     I^{A}I^{A}AS        I^{A}i^{o}AA        I^{A}i^{o}AS

I^{A}S     I^{A}I^{A}AS      I^{A}I^{A}SS         I^{A}i^{o}AS        I^{A}i^{o}SS

i^{o}A     I^{A}i^{o}AA      I^{A}i^{o}AS         i^{o}i^{o}AA        i^{o}i^{o}AS

i^{o}S     I^{A}i^{o}AS       I^{A}i^{o}SS         i^{o}i^{o}AS         i^{o}i^{o}SS

\frac{3}{16}= 18.75% : Blood type A, normal hemoglobin (normal RBCs) = I^{A}I^{A}AA, I^{A}i^{o}AA, I^{A}i^{o}AA

\frac{6}{16}= 37.5% : Blood type A, normal and mutant hemoglobin (sickle cell trait) = I^{A}I^{A}AS, I^{A}i^{o}AS, I^{A}I^{A}AS, I^{A}i^{o}AS, I^{A}i^{o}AS, I^{A}i^{o}AS

\frac{3}{16}= 18.75% : Blood type A, mutant hemoglobin (sickle cell anemia) = I^{A}I^{A}SS, I^{A}i^{o}SS, I^{A}i^{o}SS

\frac{1}{16}= 6.25% : Blood type O, normal hemoglobin (normal RBCs) = i^{o}i^{o}AA

\frac{2}{16}= 12.5% : Blood type O, Blood type A, normal and mutant hemoglobin (sickle cell trait) = i^{o}i^{o}AA, i^{o}i^{o}AS

\frac{1}{16}= 6.25% : Blood type O, mutant hemoglobin (sickle cell anemia) = i^{o}i^{o}SS

I hope that helps alot!

3 0
3 years ago
List five reliable sources of health information
forsale [732]

Sources of health information are things, people or places from which health information is obtained. Sources of health information provide knowledge or inform people about issues related to health. It may be primary (original source such as diary), secondary or tertiary (such as an encyclopedia). Sources of health information include media sources such as TV, internet, health organizations, and healthcare providers.

Five reliable sources of health information are;  

1. CDC (Center of Disease Control) resource center.

2. WHO (World Health Organization) journals and essays.

3. Medical surveys with reliable sources and evidence.

4. A published doctor's magazine with reliable sources.

5. Health care providers.


8 0
3 years ago
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