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4 years ago

10

No idea. please help:)

1 answer:

Ber [7]4 years ago

8 0

The answer is in the picture

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Carlos bought 24 pounds of flour for $11 How many pounds of flour did he get per dollar?

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2.2 or 2.18

Step-by-step explanation:

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the original price of a skateboard is 50% the sale price includes 20% discount what is the sale price

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50 × 0.8 = $40 is the sale price

Step-by-step explanation:

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3 years ago

300 milliliters are equivalent to how many liters?

White raven [17]

Thanks for using brainly!B. 0.3 would be the answer.

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3 years ago

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Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

Can i have the answer to this <br> pic is below

eduard

Answer:

question 1: m = 3/2

question 2: m = 1/95

Step-by-step explanation:

Slope intercept form of equation is of form

y = mx+c

where m is the slope of line and c is the y intercept of the line.

Y intercept is point on y axis where the line intersects the y axis.

____________________________________

given

y = 3/2 x

comparing it with y = mx+c

we have m = 3/2 .

since y = 3/2 x does not have constant term so it can be taken as 0. hence c is 0

_________________________________________

slope for any two point (x1,y1) and (x2,y2) on coordinate plane is given by

slope = (x2-x1)/y2-y1)

From the given table lets take two point as (2,190) and(4,380)

Thus, slope m is given by

m = (4-2)/(380-190) = 2/190 = 1/95

m = 1/95

Though, slope can be taken by dividing y by x (y/x). It is good practice to use two point form formula as given above . Provided two points are given

Please mark it the brainliest.

4 0

3 years ago