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VikaD [51]
3 years ago
15

How many gallons of a 80​% antifreeze solution must be mixed with 100 gallons of 25​% antifreeze to get a mixture that is 70​% ​

antifreeze? Use the​ six-step method.
Mathematics
2 answers:
yaroslaw [1]3 years ago
8 0

<span>0.7X+0.25*100=0.6(100+X)
0.7X+25=60+0.6X
0.7X-0.6X=60-25
0.1X=35
X=35/0.1</span>

X=350 GALLONS OF 70%





morpeh [17]3 years ago
7 0
We have 100 gallons of 25% antifreeze.
How much of 80% antifreeze do we need to add to make a 70% solution?

.25 * 100 + .80x = .70 * 100 + x
25 + .80x = 70 + .7x
.1x = 45
x = 450 gallons of 80% must be added to make a 70% solution.


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<h2><u>$52.5</u></h2>

Step-by-step explanation:

Step one:

given data

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3 0
3 years ago
Mr. Alvarado needs 15 1/8 pounds of chicken feed to fill his feeder. He has one bag of chicken feed that weighs 3 1/2 pounds and
Crazy boy [7]

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* apply *

\frac{1^*^1}{8^*^8} =\frac{1}{8} \\\\\frac{1^*^4}{2^*^4} =\frac{4}{8} \\\\\frac{3^*^2}{4^*^2} =\frac{6}{8}

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step 2 make each fraction a improper fraction

We can do this my multiplying the big number by the denominator and adding that to the numerator.

15*8=120\\120+1=121\\\frac{121}{8} \\\\3*8=24\\24+4=28\\\frac{28}{8} \\\\2*8=16\\16+6=22\\\frac{22}{8}

now we have

\frac{121}{8} -\frac{28}{8} -\frac{22}{8}

Now we can subtract

remember when subtracting fractions you only subtract the numerators. ( so we keep the denominator as 8 )

so 121 - 28 - 22 = 71

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finally we want to change the answer back into a mixed fraction

To do this we divided 71 and 8

8 can go into 71 8 times

8 * 8 = 64

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Answer:

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4 0
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