Question

Consider a rectangle with vertices A (4, 7), B (6, 7), C (4, -1), and D (6, -1). What is the length of side CD? What is the length of side BD?

Answer 1

Same way can find BD length

Answer 2

Answer:

$CD=2\\\\BD=8$

Step-by-step explanation:

$A (4, 7)$, $B (6, 7)$, $C (4, -1)$, and $D (6, -1)$

Using Distance formula:

CD:

              $\sqrt{(6-4)^2+(-1-(-1))^2} \\\\=\sqrt{(6-4)^2+(-1+1)^2} \\\\=\sqrt{2^2+0}\\\\=\sqrt{4}\\\\ =2$

BD:

          $\sqrt{(6-6)^2+(-1-7)^2} \\\\=\sqrt{0+(-8)^2}\\\\=\sqrt{64} \\\\=8$

$CD=2\\\\BD=8$