Answer:
Explanation:
Hello,
In this case, given the amounts of water and carbon dioxide we should invert the given reaction as hydrogen will be producted rather than consumed:
Consequently, the equilibrium constant is also inverted:
In such a way, we can now propose the law of mass action:
![Kc'=\frac{[H_2][CO_2]}{[H_2O][CO]}](https://tex.z-dn.net/?f=Kc%27%3D%5Cfrac%7B%5BH_2%5D%5BCO_2%5D%7D%7B%5BH_2O%5D%5BCO%5D%7D)
And we can express it in terms of the initial concentrations of the reactants and the change 
due to the reaction extent:
![Kc'=\frac{(x)(x)}{([H_2O]_0-x)([CO]_0-x)}=1.87](https://tex.z-dn.net/?f=Kc%27%3D%5Cfrac%7B%28x%29%28x%29%7D%7B%28%5BH_2O%5D_0-x%29%28%5BCO%5D_0-x%29%7D%3D1.87)
Thus, we compute the initial concentration which are same, since equal amount of moles are given:
![[H_2O]_0=[CO]_0=\frac{0.680mol}{70.0L}=0.0097M](https://tex.z-dn.net/?f=%5BH_2O%5D_0%3D%5BCO%5D_0%3D%5Cfrac%7B0.680mol%7D%7B70.0L%7D%3D0.0097M)
Hence, solving for by using the quardratic equation or solver, we obtain:
For which the correct value is 0.00561M since the other one will produce negative concentrations of water and carbon monoxide at equilibrium. Therefore, the number of moles of hydrogen at equilibrium for the same 70.0-L container turn out:
Best regards.
Answer:
Explanation:
fluorine have gained one electron that is why the sign is -1. they both have different number of protons. They have different neutron numbers. F have 10 and O have 8.
hope this helps :)
The equilibrium state of a gas when it can hold all the molecules of water vapor is known as saturation.
<h3>Which three equilibrium conditions apply?</h3>
A solid substance subjected to three forces with divergent lines of action is in equilibrium if all three of the following three circumstances hold true:
- Coplanar action lines are present (in the same plane)
- The paths of action have come together (they cross at the same point)
- These forces add up to a vector with a total of zero.
<h3>What are equilibrium's first and second conditions?</h3>
An object must satisfy two requirements of equilibrium in order to maintain static equilibrium.
- First, there must be no net force acting on the item.
- Second, there must be no net torque pulling on the object.
learn more aboute quilibrium condition here
<u>brainly.com/question/517289</u>
#SPJ4
