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2 years ago

How can you make the polymer stretch the farthest?

Chemistry

2 answers:

aleksandrvk [35]2 years ago

5 0

Borax with salt and glue

Zinaida [17]2 years ago

5 0

Mix borax with water and glue and there you go

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If 26.2 grams of a pure compound contain 8.77 × 1022 molecules, what is the molecular weight of this compound? Answer in units o

Nataly [62]

Answer:

Mw = 179.845 g/mol

Explanation:

Mw [=] g/mol

∴ w = 26.2 g

∴ 1 mol = 6.02 E23 molecules.......Avogadro's number

⇒N° moles = 8.77 E22 molecules * ( mol / 6.02 E23 molecules ) = 0.146 mol

⇒ Mw = 26.2 g / 0.146 mol = 179.845 g/mol

3 0

2 years ago

The frequency of an x-ray wave is 3.0 x 1012 MHz. Its wave speed is 3.0x 108 m/s. Calculate the wavelength of the x-ray wave bel

elena55 [62]

Answer:

λ = 1*10⁻¹⁰m

Explanation:

Frequency (f) = 3.0*10¹²MHz = 3.0*10¹⁸Hz

Speed (v) = 3.0*10⁸m/s

Speed (v) of a wave = frequency (f) * wavelength (λ)

V = fλ

Solve for λ,

λ = v / f

λ = 3.0*10⁸ / 3.0*10¹⁸

λ = 1*10⁻¹⁰m

λ = 0.

6 0

2 years ago

Green plants absorbs sunlight to power photosynthesis, the chemical synthesis of food from water and carbon dioxide. The compoun

Serggg [28]

Answer: The frequency of this light is $6.62\times 10^{14}s^{-1}$

Explanation:

To calculate the wavelength of light, we use the equation:

$\lambda=\frac{c}{\nu}$

where,

$\lambda$ = wavelength of the light = $453nm=453\times 10^{-9}m$

c = speed of light = $3.0\times 10^8m/s$

$\nu$ = frequency of light = ?

$\nu=\frac{3.0\times 10^8m/s}{453\times 10^{-9}m}=6.62\times 10^{14}s^{-1}$

The frequency of this light is $6.62\times 10^{14}s^{-1}$

3 0

2 years ago

A 50.0 g sample of scandium, sc, is heated by exposure to 1.50 x 10 3 j. The temperature of the sc is raised by 61.1 o

statuscvo [17]

Given mass of Scandium = 50.0 g

Increase in temperature of the metal when heated = $61.1^{0}C$

Heat absorbed by Scandium = $1.50*10^{3}J$

The equation showing the relationship between heat, mass, specific heat and temperature change:

$Q = m C (deltaT)$

Where Q is heat = $1.50*10^{3}J$

m is mass = 50.0 g

ΔT = $61.1^{0}C$

On plugging in the values and solving for C(specific heat) we get,

$1.50*10^{3}J$ =50.0g(C)( $61.1^{0}C$ )

C = 0.491 $\frac{J}{g^{0}C }$

Specific heat of the metal = 0.491 $\frac{J}{g^{0}C }$

7 0

2 years ago

Why amorphous solids are called super cooled liquids?

qwelly [4]

Because this classification contrasts with that of crystalline solids whose atoms are arranged in a regular and orderly fashion forming crystalline networks.

3 0

2 years ago