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Goryan [66]
4 years ago
12

PLEASE HELP I HAVE NO IDEA WHAT TO DO

Chemistry
1 answer:
DanielleElmas [232]4 years ago
3 0

Answer:

For density you divide the mass by cm so for trail one the answer would be  34.31/1.64=20.9

Explanation:

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How many mL of 0.013 M potassium hydroxide are required to reach the equivalence point in the titration of 75 mL 0.166 M hydrocy
umka21 [38]

Answer:

957.7mL

Explanation:

Using the formula below;

CaVa = CbVb

Where;

Ca = concentration of acid (M)

Va = volume of acid (mL)

Cb = concentration of base (M)

Vb = volume of base (mL)

According to the information provided in this question:

Ca = 0.166 M

Cb = 0.013 M

Va = 75mL

Vb = ?

Using CaVa = CbVb

0.166 × 75 = 0.013 × Vb

12.45 = 0.013Vb

Vb =12.45/0.013

Vb = 957.7mL

6 0
3 years ago
Which equation best describes the net changes based upon the observation that solid silver nitrate and solid potassium chloride
stealth61 [152]

Answer:

The correct option is: AgNO₃(aq) + KCl(aq) = AgCl(s) + KNO₃(aq)  

Explanation:

Precipitation reaction is a chemical reaction that involves reaction between <em>two soluble salts to give an insoluble salt.</em> This <u>insoluble salt exists as a solid</u> and settles down.

Therefore, the solid formed in a precipitation reaction is known as the precipitate.  

As the solid silver nitrate (AgNO₃) and solid potassium chloride (KCl) are <u>soluble in water</u>, therefore, their aqueous solutions are represented as AgNO₃(aq) and KCl(aq), respectively.

The precipitation reaction of AgNO₃(aq) and KCl(aq) gives an <u>insoluble salt, silver chloride (AgCl) and a soluble salt, potassium nitrate (KNO₃).</u>

The insoluble salt, <u>AgCl is called the precipitate</u> and is represented as AgCl(s). Whereas, the <u>soluble salt</u>, KNO₃ is represented as KNO₃ (aq).

<u>Therefore, the chemical equation for this precipitation reaction is:</u>

AgNO₃(aq) + KCl(aq) → AgCl(s) + KNO₃(aq)

6 0
3 years ago
A mixture of 14.0 grams of H2, 84.0 grams of N2, and 64.0 grams of O2 are placed in a flask. The partial pressure of the O2 is 7
Hitman42 [59]

Answer:

P_{tot}=465.27torr

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to use the Dalton's law, in order to solve this problem. However, we first need to calculate the mole fraction of oxygen by firstly calculating the moles of each gas:

n_{H_2}=\frac{14.0g}{2.02g/mol} =6.93mol\\\\n_{N_2}=\frac{84.0g}{28.02g/mol}=3.00mol\\\\n_{O_2}=\frac{64.0}{16.00g/mol}  =2.00mol

Next, we calculate such mole fraction as follows:

x_{O_2}=\frac{2}{6.93+3+2} =0.168

Then, given the following equation:

P_{O_2}=P_{tot}*x_{O_2}

So we solve for the total pressure as follows:

P_{tot}=\frac{P_{O_2}}{x_{O_2}} \\\\P_{tot}=\frac{78.00torr}{0.168} \\\\P_{tot}=465.27torr

Regards!

6 0
3 years ago
What's the formula for hypoarsenous acid?
seraphim [82]

Answer:

As(OH)3 or AsH3O3

Explanation:

3 0
3 years ago
Read 2 more answers
A gas occupies a volume of 410 mL at 27°C and 740 mm Hg pressure. Calculate the volume the gas
murzikaleks [220]

Answer:

The volume of gas is 58.22 L which will occupy at 250.°C and 680 mm Hg pressure.

Explanation:

Given:

Temperature = 27°C

To make it into kelvin   = 27+273

 = 300K

Pressure  =740mm Hg

to make it in atm.  = \frac{740}{760}

= 0.973atm

n   = 2.3 moles

Volume of gas =?

 As we know according to the formula

 PV   = nRT

V= \frac{nRT}{P}

On substituting the values

 = \frac{2.3\times0.0827\times300}{0.973}

= 58.22 L

Therefore, 58.22L volume of gas will occupy at 250.°C and 680 mm Hg pressure.

8 0
3 years ago
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