Answer:
Im not 100% sure but i think its option two or 1
Explanation:
Answer:
Mass = 25.08 g
Explanation:
Given data:
Volume of fluorine = 29.6 L
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Mass of fluorine = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm × 29.6 L / 0.0821 atm.L/ mol.K × 273.15 K
n = 1.32 mol
Mass of fluorine:
Mass = number of moles × molar mass
Mass = 1.32 mol ×19 g/mol
Mass = 25.08 g
Answer:
167,3 grams of O2 (g)
Explanation:
According to the following balanced equation:
C3H8 + 5 02 ---> 3 CO2 + 4 H20
We calculate the mass of the moles:
5 mol O2 = 16grams/mol x2x 5= 160 grams/mol
1 mol C3H8= 3 x12 grams/mol + 8 x 1 gram/mol= 44 grams/mol
If 44 grams C3H8 react with--------- 160 grams O2
46 gramsC3H8 react with --------X = (46x160)/44 =167, 3 grams O2
Answer: n∗R=22+273.15/4.2∗5n
P2=n∗R∗T2/V2=n∗R∗33.6+273.15/10
Explanation:
