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satela [25.4K]
3 years ago
12

Use the linear combination method to solve this system of equations. What is the value of x?

Mathematics
2 answers:
Semmy [17]3 years ago
7 0
X=1 because when u put it in then u will find out.y=-1
zepelin [54]3 years ago
4 0

Answer:

x=1

Step-by-step explanation:

We are going to use the matching method, it consists in clear the same incognits in both equations and macth those results. Steps below:

<u>First equation: </u>

-2.4x-3.6y=1.2

-3.6y=1.2+2.4x

y=(1.2+2.4x)/(-3.6)    

<u>Second equation:</u>

2.4x+1.2y=1.2

1.2y=1.2-2.4x

y=(1.2-2.4x)/(1.2)

Now we have to match both equations and clear the incognit <em>x</em>

(1.2+2.4x)/(-3.6) = (1.2-2.4x)/(1.2)

(1.2+2.4x) = (1.2-2.4x) *(-3.6)/(1.2)

1.2+2.4x = (1.2-2.4x) *(-3)

1.2+2.4x = -3.6+7.2x

2.4x-7.2x = -3.6-1.2

-4.8x = -4.8

x = (-4.8)/(-4.8)

<em>x = 1</em>

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Solve the inequalities for x, and match each solution to its number line graph.
marysya [2.9K]

Answer:

14

Step-by-step explanation:

8 0
3 years ago
Solve the absolute value inequality: |8x + 5| &gt; 15. Express using interval notation
kirill [66]

Answer:

8 < 2

Step-by-step explanation:

8x + 5 > 15

8x > 15 - 5

8x > 10

x < 2

cmiiw

5 0
3 years ago
The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l
mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: (\frac{n+1}{2}) th\ term

Putting n=21

(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

<u>For First Half:</u>

98, 100, 101, 102, <u>108, 109</u>, 111,118, 129, 132

Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5

<u>For Second Half:</u>

135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151

Now

<u>Interquartile Range:</u>

IQR = Q_3-Q_1\\= 151-108.5\\=42.5

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

  • brainly.com/question/10940255
  • brainly.com/question/10941043

#LearnwithBrianly

7 0
3 years ago
Find three consecutive numbers such that the sum of one-fourth the first and one-fifth the second is five less than one-seventh
mafiozo [28]

Answer:

The numbers are -16,-15 and -14

Step-by-step explanation:

Let

x ----> the first number

x+1 ----> the second number

x+2 ---> the third number

we know that

(1/4)x+(1/5)(x+1)=(1/7)(x+2)-5

Multiply by (4*5*7) both sides

35x+28(x+1)=20(x+2)-140*5

35x+28x+28=20x+40-700

43x=-688

x=-16

so

x+1=16+1=-15

x+2=-16+2=-14

The numbers are -16,-15 and -14

5 0
4 years ago
Need help please help mee.. (dont answer if u dont know how to do it
vivado [14]

Answer:

4,38.8

Step-by-step explanation:

but u dont want my help srry

3 0
3 years ago
Read 2 more answers
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