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CaHeK987 [17]
3 years ago
5

Segment RT is a mid-segment of triangle CDE. What is the length of segment CE?

Mathematics
1 answer:
PtichkaEL [24]3 years ago
7 0
Segment RT is a mid-segment of triangle CDE
so CE = 2(RT) = 2(19) = 38

answer
A. 38
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Answer:

Option C is correct.

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Step-by-step explanation:

Given the equation: 3x^2+10 = 4x

We can write this equation as:

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A quadratic equation is in the form of ax^2+bx+c =0      ......[1] where a,b ,c are the coefficient and x is the variable,

the solution of the equation is given by;

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or

x =\frac{4\pm2 \sqrt{(-26)}}{6} = \frac{4\pm2 i\sqrt{26}}{6}    [∴\sqrt{-1} = i

Simplify:

x =\frac{2\pm i\sqrt{26}}{3}

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