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morpeh [17]
4 years ago
15

Identify the effect of increasing acidity on the solubility of the given compounds.

Chemistry
1 answer:
Ilia_Sergeevich [38]4 years ago
4 0

All the given compounds are basic on acidifying their solubility increases.

<u>Explanation:</u>

  • C a_{3}\left(P O_{4}\right)_{2} solubility will increase, since it is basic in nature, on acidifying  solubility increases.
  • F e S being basic on acidification, the solubility increases.
  • M g C O_{3} is alkaline in nature, it gets neutralized and there is no increase in acidity.
  • M g B r_{2} is a salt and it shows no effect on acidification.
  • A g I is a salt but insoluble in water and shows no effect on acidification.
  • M g(O H)_{2} is strongly basic in nature, on acidifying the solubility increases.
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Answer:

2M

Explanation:

M=mol/L

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The isotope of an atom containing 31 protons and 39 neutrons suddenly has two neutrons added to it.
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Answer:

Gallium-72

Explanation:

The elements are identified by the number of protons of the atom, which is its atomic number.

In this case the number of protons 39 (atomic number 39) permit you to identify the element as gallium.

Now, to identify the isotope you tell the name of the element and add the mass number.

The mass number is the sum of the protons and the neutrons

In this case, the number of neutrons is the original 39 plus the 2 added suddenly, i.e. 39 + 2 = 41, so the mass number is 31 + 41 = 72

Therefore, the isotope is gallium - 72.

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3 years ago
if 15 mol C is mixed with 10 mol O2 which reactant is the limiting reactant? Which reactant would be the excess reactant?
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C is the excess reactant.

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1mol of C required to react with 1mol O2

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