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3 years ago

There are 20 mice in a 5 m2 field ecosystem. The population density of mice is _____.

1 answer:

6 0

The formula for density = number/ area
In this case number=20
area = 5m^2

Density = 20/5=4 mice per m^2
The right answer is A. 4 per m2

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Pls help help help psl

sergejj [24]

Answer:

IF TWO VALUES ARE PROPORTIONAL THEY CAN BE CONNECTED IN TERMS OF k BY MAKING THEM IN A STUCTURE OF AN EQAUTION LIKE GIVEN BELOW. HERE AS THE PROPORTIONAL VALUES ARE RADIUS AND CIRCUMFERENCE WE USE THE GIVEN VALUES AND CREATE EQAUTION LIKE BELOW

r=kC

⇒WE CAN TRASNPOSE THIS TO GET

kC/r=0

⇒C/r=1/k

RECIPROCATE IT TO GET

⇒r/C=k

Maybe this will be correct answer

4 0

3 years ago

Read 2 more answers

If angle x=55% and angle y=35, calculate the following 1.cos(x+y)

Setler79 [48]

Answer:

cos(X+Y) = cos(55+35) = cos(90) = 0

Step-by-step explanation:

cos(X+Y) = cosXcosY - sinXsinY

cos(55+35) = cos(55)cos(35) - sin(55)sin(35)

cos(55+35) = cos(55)cos(35) - cos(90-55)cos(90-35)

cos(55+35) = cos(55)cos(35) - cos(35)cos(55)

cos(55+35) = 0

cos(90) = 0

4 0

3 years ago

How would i solve these two problems?

Montano1993 [528]

Number 17 9216 because you take 96*4

8 0

3 years ago

Please help fast......

Tom [10]

$\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\ 1.AY=BX&\text{1. Given}\\ 2.AB \cong AB&\text{2. Reflexive Property}\\ 3. AD || BC&\text{3. Property of a square}\\ 4. \angle ABE \cong \angle AXB&\text{4. Alternate Interior Angles}\\ 5. \angle BAY \cong \angle BYA&\text{5. Alternate Interior Angles}\\6. \triangle BAX \cong \triangle ABY&\text{6. Angle-Side-Angle Theorem}\\ 7. AX \cong BY&\text{7. CPCTC}\\\end{array}$

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$\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\1. AB=CF&\text{1. Given}\\2.AB+BF=A'F&\text{2. Segment Addition Postulate}\\3.CF+BF=A'F&\text{3. Substitution Property}\\4.CF+BF+BC&\text{4. Segment Addition Postulate}\\5.A'F=BC&\text{5. Transitive Property}\\6. \angle AFE = \angle DBC&\text{6. Given}\\7. EF = BD&\text{7. Given}\\8. \triangle AFE \cong \triangle CBD&\text{8. Side-Angle-Side Theorem}\\\end{array}$

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$\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\\text{1.AC bisects }\angle BAD&\text{1. Given}\\2. \angle BAC \cong \angle DAC&\text{2. Property of angle bisector}\\3.AC = AC&\text{3. Reflexive Property}&4. \angle ACB \cong \angle ACD&\text{4. Property of angle bisector}\\5. \triangle ABC \cong \triangle ADC&\text{5. Angle-Side-Angle Theorem}\\6.BC=CD&\text{6. CPCTC}\\\end{array}$

5 0

3 years ago

True or false? Do the following set of ordered pairs represent a function {(8,1),(0,-1),(9,4),(-6,-7),(8,9)}

Anika [276]

Hi there!

Unfortunately, the set of ordered pairs does NOT represent a function! This is because there are two of the same x values. In a function, there is one input for every output. In this case, there are two of the same inputs. However, there can be two of the same outputs.
Just to clarify - Not a function

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

6 0

3 years ago