X+y=5 3x+3y=10 eliminacion

ill in the missing numbers along the sides of the triangle so that it contains each of the numbers from through exactly once.

mihalych1998 [28]

Each side of the triangle should contain four numbers whose sum is 28.

3+5+9+11=28

3+10+8+7=28

11+6+9+7=28

The pain of numbers that can be used for A and B is [5,9] The pain of numbers that can be used for C and D is [10,8] and the pain of numbers that can be used for E and f is [6,4].

<h3>What are the 3 sides of a triangle?</h3>

The hypotenuse of a right triangle is its longest side; its "opposite" side is the one that faces the angle in question; and its "adjacent" side is the one that faces it. We use special terminology to define the sides of right triangles.

We use special terminology to define the sides of right triangles.

The side opposite the right angle is always the hypotenuse of a right triangle. It is the longest side in a right triangle.

The opposing and neighboring sides are the other two sides. The labels on these sides relate to an angle.

One side is across from another at a particular angle.

To learn more about sides of a triangle visit:

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5 0

10 months ago

Someone help plss show work

Mazyrski [523]

Answer:

Slope: $\frac{3}{5}$

Y-Intercept: $(0,-5)$

Step-by-step explanation:

1. To find the slope, we need to have the equation in slope-intercept form, which is $y=mx+b$ . In this case, our equation is already in this form. $m$ is what your slope is. In this case, our

2. To find the y-intercept we look at value $b$ that is in $y=mx+b$ . In this case, $b$ is $-5$ . So, our ordered pair is $(0,-5)$ .

4 0

2 years ago

Read 2 more answers

2. Suppose over several years of offering AP Statistics, a high school finds that final exam scores are normally distributed wit

nirvana33 [79]

Answer:

By the Central Limit Theorem, the mean is 78, the standard deviation is $s = \frac{6}{\sqrt{n}}$ and the shape is approximately normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .