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NeX [460]
3 years ago
6

Help plz!!!

Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0

Answer:

First graph

Step-by-step explanation:

First off, the graph opens up because <em>a</em> is positive. Second, the parent function of the quadratic graph is \displaystyle y = x^2,and the greater the WHOLE NUMBERS [vertical stretch (<em>a</em>)] get, the slimmer the parabola gets, and the more you increase the DEGREE evenly [anything ending in 0, 2, 4, 6, and\or 8], the more flat, U-shaped the parabola becomes.

I am joyous to assist you anytime.

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jek_recluse [69]

Answer:

Choice B: y = 2\, (x - 6)^{2} + 5.

Step-by-step explanation:

For a parabola with vertex (h,\, k), the vertex form equation of that parabola in would be:

\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}.

In this question, the vertex is (6,\, 5), such that h = 6 and k = 5. There would exist a constant a such that the equation of this parabola would be:

y = a\, (x - 6)^{2} + 5.

The next step is to find the value of the constant a.

Given that this parabola includes the point (7,\, 7), x = 7 and y = 7 would need to satisfy the equation of this parabola, y = a\, (x - 6)^{2} + 5.

Substitute these two values into the equation for this parabola:

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Step-by-step explanation:

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