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Alchen [17]
4 years ago
5

Your TLC results for ortho-hydroxyacetophenone versus para-hydroxyacteophenone will indicate that one compound is significantly

less polar than the other. Based on an analysis of polarity (using only dipole moments and electronegativities), which compound would you expect to be more polar?
Chemistry
1 answer:
Sloan [31]4 years ago
7 0

Answer:

2-hydroxy

Explanation:

The 4-hydroxy has a reduced dipole because its two electronegative substituents give it a dipole in opposite directions. On the other hand the 2-hydroxy has dipoles that add together.

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Is cereal soup? and Is an hot dog a sandwich?...
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Answer: Cereal is considered a soup and a hot dog is considered a

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3 years ago
How does the amount of carbon dioxide affect the rate of photosynthesis?
julsineya [31]

Answer:

There are several ways of measuring the rate of photosynthesis in the lab. These include:

the rate of oxygen output

the rate of carbon dioxide uptake

the rate of carbohydrate production

These are not perfect methods as the plant will also be respiring, which will use up some oxygen and carbohydrate and increase carbon dioxide output.

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4 0
3 years ago
How do people start alcohol consumption​
Debora [2.8K]

Answer:

Explanation:Due to the mental pressure,

                       Due to peer pressure,

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6 0
3 years ago
During an experiment, 104 grams of calcium carbonate reacted with an excess amount of hydrochloric acid. If the percent yield of
postnew [5]

Answer:

92.4 grams.

Explanation:

  • From the balanced reaction:

<em>CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O,</em>

1.0 mole of CaCO₃ reacts with 2.0 moles of HCl to produce 1.0 mole of CaCl₂, 1.0 mole of CO₂, and 1.0 mole of H₂O.

  • We need to calculate the no. of moles of (104 g) of CaCO₃:

<em>no. of moles of CaCO₃ = mass/molar mass</em> = (104 g)/(100.08 g/mol) = <em>1.039 mol.</em>

<u><em>Using cross multiplication:</em></u>

1.0 mole of CaCO₃ produce → 1.0 mole of CaCl₂.

∴ 1.039 mole of CaCO₃ produce → 1.039 mole of CaCl₂.

∴ The amount of CaCl₂ produced = no. of moles x molar mass = (1.039 mol)(110.98 g/mol) = 114.3 g.

∵ percent yield of the reaction = [(actual yield)/(theoretical yield)] x 100.

Percent yield of the reaction = 80.15%, theoretical yield = 115.3 g.

<em>∴ actual yield = [(percent yield of the reaction)(theoretical yield)]/100 </em>= [(80.15%)/(115.3 g)] / 100 = <em>92.42 g ≅ 92.4 g.</em>

7 0
3 years ago
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