Answer:
<u>only sodium chloride compounds</u> MOST LIKELY products of the reaction between sodium metal and chlorine gas.
Correct answer - C
Explanation:
A solid sodium metal reacts with gaseous form of chlorine gas to form a solid sodium chloride.
This formation of sodium chloride arises due to transfer of one valence electron from sodium to chlorine atom and the both atoms get stable octet electronic configuration.
As a result, an ionic compound solid sodium chloride is formed.
The chemical reaction of formation sodium chloride is as follows.
Therefore, <u>only sodium chloride compounds</u> MOST LIKELY products of the reaction between sodium metal and chlorine gas.
Answer: The ground-state electronic configuration of
1) ![Ru^{2+}=[Kr]4d^6](https://tex.z-dn.net/?f=Ru%5E%7B2%2B%7D%3D%5BKr%5D4d%5E6)
2) ![W^{3+]=4f^{14}5d^3](https://tex.z-dn.net/?f=W%5E%7B3%2B%5D%3D4f%5E%7B14%7D5d%5E3)
Explanation: The electronic configuration of elements is defined as the distribution of electrons around the nucleus of that element. It depends on the atomic number of the element.
Atomic number of the element = Number of electrons.
Atomic number = 44
Number of electrons = 44
Electronic configuration of Ru-element = ![[Kr]4d^75s^1](https://tex.z-dn.net/?f=%5BKr%5D4d%5E75s%5E1)
To form 
, 2 electrons are released from the neutral Ru-element.
So, the electronic configuration of
Atomic number = 74
Number of electrons = 74
Electronic configuration of W-element = ![[Xe]4f^{14}5d^46s^2](https://tex.z-dn.net/?f=%5BXe%5D4f%5E%7B14%7D5d%5E46s%5E2)
To form 
, 3 electrons are released from the neutral W-element.
So, the electronic configuration of ![W^{3+}=[Xe]4f^{14}5d^3](https://tex.z-dn.net/?f=W%5E%7B3%2B%7D%3D%5BXe%5D4f%5E%7B14%7D5d%5E3)
Answer:
The degree of compactness of a substance
Answer:
23.46 mmHg is the vapor pressure for the solution
Explanation:
To solve this problem we need to apply a colligative property, which is the lowering vapor pressure.
The formula for this is: P°- P' = P° . Xm
where P' is vapor pressure for solution and P°, vapor pressure for pure solvent.
Let's determine the Xm (mole fraction for solute)
We calculate the moles of the solute and the solvent and we sum each other:
Moles of solute: 60 g /342 g/mol = 0.175 moles of sucrose
Moles of solvent: 250 g / 18 g/mol = 13.8 moles of water
Total moles: 13.8 moles + 0.175 moles = 13.975 moles
Xm for solute: 0.175 moles / 13.975 moles = 0.0125
Let's replace data in the formula: 23.76 mmHg - P' = 23.76 mmHg . 0.0125
P' = - (23.76 mmHg . 0.0125 - 23.76 mmHg) → 23.46 mmHg
