Question

Two forces act on an object. The first force has a magnitude of 15.0 N15.0 N and is oriented 58.0°58.0° counterclockwise from the +x+x ‑axis, whereas the second force has xx ‑ and yy ‑components (−19.0 N,18.5 N).(−19.0 N,18.5 N). Express the magnitude and direction of the net force.

Answer 1

Answer:

F = 33.12 N

Explanation:

given,

first force = 15 N is oriented at 58.0° counterclockwise

second force  = (−19.0 N,18.5 N)

x-component of first force = 15 cos 58.0° = 7.95 N

y-component of second force = 15 sin 58.0° = 12.72 N      

second component                      

now,

F netx = 7.95 - 19 = -11.05 N

F nety = 12.72 + 18.5 = 31.22 N          

$F=\sqrt{(-11.05)^2+31.22^2}$

F = 33.12 N

$tan \theta = -\dfrac{31.22}{11.05}$

θ = -70.51°